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Yuri [45]
3 years ago
9

The "air bags" that are currently installed in automobiles to prevent injuries in the event of a crash are equipped with sodium

azide, NaN₃, which decomposes when activated by an electronic igniter to produce nitrogen gas that fills the bag. How many liters of nitrogen, measured at 25°C and 1.00 atm, will be produced by 100.0 g of NaN₃?
Chemistry
1 answer:
stellarik [79]3 years ago
3 0

Answer:

0.0177 L of nitrogen will be produced

Explanation:

The decomposition reaction of sodium azide will be:

2NaN_{3}(s)--->2Na(s)+3N_{2}(g)

As per the balanced equation two moles of sodium azide will give three moles of nitrogen gas

The molecular weight of sodium azide = 65 g/mol

The mass of sodium azide used = 100 g

The moles of sodium azide used = \frac{mass}{molarmass}=\frac{100}{65}=1.54mol

so 1.54 moles of sodium azide will give = \frac{3X1.54}{2}=2.31mol

the volume will be calculated using ideal gas equation

PV=nRT

Where

P = Pressure = 1.00 atm

V = ?

n = moles = 2.31 mol

R = 0.0821 L atm / mol K

T = 25 °C = 298.15 K

Volume = \frac{P}{nRT}=\frac{1}{2.31X0.0821X298.15}=0.0177L

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A flashlight battery is hooked to a toy motor, and then the battery and the connections are sprayed with a water-proof coating.
denis-greek [22]

Explanation:

Formula to calculate work done by motor is as follows.

         Work done by motor = mass \times g \times height

where,   g = gravitational constant = 10 m/s^{2}

Therefore, work done by motor is as follows.

 Work done by motor = 1.00 kg \times 10 m/s^{2} \times 10.0 m  

                                  = 100.0 J

Now, heat lost by water will be calculated as follows.

            q = mC \times \Delta T

                = g \times 4.184 J/g^{o}C \times 0.024^{o}C

                = 10.0 J

Hence, heat gained by motor = heat lost by water

As, heat gained by motor = 10.0 J

So, change in energy = heat gained - work done

Therefore, change in energy will be calculated as follows.  

   Change in energy = heat gained - work done

                                  = (10.0 J) - (100.0 J)

                                   = -90.0 J

Thus, we can conclude that change in the energy of the battery contents is -90.0 J.

4 0
2 years ago
Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
Read 2 more answers
From goal line to goal line, a football field is 300 ft long. If a player catches the ball while standing on one goal line, runs
KATRIN_1 [288]

Answer:

The player ran 91.44m.

Explanation:

The problem gives you the total distance between goal line to goal line in feet, and the answer must be given in meters, so you should convert the distance the player run from ft to m, because the player run the same distance from goal line to goal line to scores the touchdown.

So, you should apply the following conversion factor:

300ft*\frac{0.3048m}{1ft}= 91.44m

The player ran 91.44m.

3 0
3 years ago
A rock dropped in a graduated cylinder raises the level of water from 20 mL to 35 mL. The rock has a mass of 45 g. What is the d
Brut [27]
I think 15 I might be wrong
7 0
3 years ago
What is the meaning of the term polar as applied to chemical bonding?
kicyunya [14]
Polar<span> covalent </span>bonding<span> is a type of </span>chemical bond <span>where a pair of electrons is unequally shared between two atoms.</span>
8 0
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