Answer:
292.4 g
Explanation:
- 2Al + 3H₂SO₄ → 3H₂ + Al₂(SO₄)₃
First we <u>convert 53.7 g of Al into moles</u>, using its<em> molar mass</em>:
- 53.7 g ÷ 27 g/mol = 1.99 mol Al
Then we <u>convert Al moles into H₂SO₄ moles</u>, using the <em>stoichiometric coefficients</em>:
- 1.99 mol Al * = 2.98 mol H₂SO₄
Finally we <u>convert 2.98 moles of sulfuric acid into gram</u>s, using its <em>molar mass:</em>
- 2.98 mol H₂SO₄ * 98 g/mol = 292.4 g
Answer:
bbbbbbbb. bbbbbbbbbbbbbbbbbbbb?!?! bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb :)
Explanation:
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The empirical formula of the compound containing 0.64 g of copper, 0.32 g of sulphur and 0.64 g of oxygen is CuSO₄
From the question given above, the following data were obtained:
Mass of Cu = 0.64 g
Mass S = 0.32 g
Mass of O = 0.64 g
<h3>Empirical formula =? </h3>
The empirical formula of the compound can be obtained as follow:
Cu = 0.64 g
S= 0.32 g
O = 0.64 g
Divide by their molar mass
Cu = 0.64 / 63.5 = 0.01
S= 0.32 / 32 = 0.01
O = 0.64 / 16 = 0.04
Divide by the smallest
Cu = 0.01 / 0.01 = 1
S= 0.01 / 0.01 = 1
O = 0.04 / 0.01 = 4
Therefore, the empirical formula of the compound is CuSO₄
Learn more: brainly.com/question/13086832
The total number of electron pairs that are shared between the two carbon atoms in a molecule of ethyne is 3.
Answer:
potential energy (im positive that its right)