3.9 x 10³g
Explanation:
Given parameters;
concentration = 48g/m³
Room dimension = 12 x 12.5 x 18.5ft
unknown:
Mass of carbon dioxide in the room = ?
Solution:
We know that in a room the concentration of carbon monoxide is 48g/m³
To find the mass of the carbon monoxide in a given room, we simply multiply the given concentration level with the volume of the room.
Mass of carbon monoxide = concentration x volume of room
To find the volume of room;
Dimension = 12 x 12.5 x 18.5 in ft to m;
1ft = 0.31m
12ft to meter is 0.31 x 12 = 3.72m
12.5ft to meter is 0.31 x 12.5 = 3.88m
18.5ft to meter is 0.31 x 18.5 = 5.74m
Volume of the room = 3.72 x 3.88 x 5.74 = 82.8m³
Mass of carbon monoxide = concentration x volume of room
Mass of carbon monoxide = 48 x 82.8 = 3.9 x 10³g
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<h3><u>Answer;</u></h3>
- <u>0.433 g N2 </u>
- <u>0.293 g O2 </u>
- <u>0.0367 g He</u>
<h3><em>Explanation and solution;</em></h3>
- We can start by getting the total pressure; which will be the sum of the partial pressure of each gas.
221 torr + 131 torr + 131 torr
P (total) = 483 torr total
n = PV / RT, we can determine the total number of moles of the mixture
= (483 torr) x (1.30 L) / ((62.36367 L Torr/K mol) x (25.0 + 273.15 K))
= 0.033769 mol gases total
-
Therefore; we can determine the mass of each gas;
- <u>Nitrogen gas </u>
<em>N2 = 28.01 g/mol</em>
<em>= (0.033769 mol) x ( 221 torr N2/ 483 torr) x (28.01 g N2/mol) </em>
<u>= 0.433 g N2 </u>
<em>
O2 = 32 g/ mol </em>
<em> =(0.033769 mol) x (131 torr O2/ 483 torr) x (32 g O2/mol)</em>
<em> </em><em><u>= 0.293 g O2 </u></em>
- <em><u>Helium gas </u></em>
<em><u>
</u></em><em>He = 4 g/mol</em>
<em>= (0.033769 mol) x (131 torr He/ 483 torr) x (4.00 g He/mol) </em>
<em><u>= 0.0367 g He</u></em>
Object A at 40
degrees C and object B at 80 degrees C are placed in contact with each other.
The heat flow will flow from the Object B to the object A because of temperature
difference. To attain equilibrium, the heat flow must flow form a higher
temperature to a lower temperature.
The answer is, 699g
The idea here is that you need to use the mole ratio<span> tha exists between </span>ferric oxide<span>, </span><span><span>Fe2</span><span>O3</span></span><span>, and iron metal, </span>Fe<span>, to determine how many moles of the latter will be produced when </span>all the given mass<span> of the ferric oxide reacts...
</span>