On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the loc
ation and size of the image. F labels the focal point of the mirror.
You do not have to trace additional rays for this question.
Answer:
You do not have to trace additional rays for this question.
Answer:
1 answer:
Answer:
<u></u>
- <u>See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.</u>
Explanation:
The <em>curved mirror</em> shown is a converging lens.
<em>To find the location and size of the image</em> formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (<em>Ray 1</em> in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.
The attached figure shows this ray in blue.
The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).
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Answer:
As the concentration of a solute in a solution increases, the freezing point of the solution <u><em>decrease </em></u>and the vapor pressure of the solution <em><u>decrease </u></em>.
Explanation:
Depression in freezing point :
where,
=depression in freezing point =
= freezing point constant
m = molality ( moles per kg of solvent) of the solution
As we can see that from the formula that higher the molality of the solution is directly proportionate to the depression in freezing point which means that:
- If molality of the solution in high the depression in freezing point of the solution will be more.
- If molality of the solution in low the depression in freezing point of teh solution will be lower .
Relative lowering in vapor pressure of the solution is given by :
= Vapor pressure of pure solvent
= Vapor pressure of solution
= Mole fraction of solute
Vapor pressure of the solution is inversely proportional to the mole fraction of solute.
- Higher the concentration of solute more will the be solute's mole fraction and decrease in vapor pressure of the solution will be observed.
- lower the concentration of solute more will the be solute's mole fraction and increase in vapor pressure of the solution will be observed.