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Papessa [141]
3 years ago
11

On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the loc

ation and size of the image. F labels the focal point of the mirror.
You do not have to trace additional rays for this question.
Answer:

Physics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

<u></u>

  • <u>See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.</u>

Explanation:

The <em>curved mirror</em> shown is a converging lens.

<em>To find the location and size of the image</em> formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (<em>Ray 1</em> in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.

The attached figure shows this ray in blue.

The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).

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anastassius [24]

Answer:

Increase the radius of curvature of surface.

Explanation:

Radius of curvature is the measurement that is two times the focal length, for a given lens. It lies on either side of the lens.

Focal length is the distance which is half of the radius of curvature. Radius of curvature is a measure of the radius of the circle . Focal length is the distance between the center of curvature of the lens and the point where all the rays are brought to a focus for a distant object.

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A coin has a radius of 1.06 cm and a thickness of 1.2 mm. Find its<br><br> volume in m^3.
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Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³

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Explanation:

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