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Papessa [141]
3 years ago
11

On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the loc

ation and size of the image. F labels the focal point of the mirror.
You do not have to trace additional rays for this question.
Answer:

Physics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

<u></u>

  • <u>See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.</u>

Explanation:

The <em>curved mirror</em> shown is a converging lens.

<em>To find the location and size of the image</em> formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (<em>Ray 1</em> in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.

The attached figure shows this ray in blue.

The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).

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Need help asap please and thank you​
nordsb [41]
Distance = speed x time

distance = 116 x 10

distance = 1160 m
6 0
3 years ago
Physics Unit 5 CA - Conservation of
Gemiola [76]

Answer:

160 kg

Explanation:

f = ma

100 = m * a

a = v/t

v = distanc/time

dist = 40m

time = 8 sec

v = 40/8

a = 40/(64)= 5/8

m = 100*8/5= 160 kg

8 0
3 years ago
A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres
Lemur [1.5K]

Answer:

V_2 = 0.125 m^3

Work done =  = 5 kJ

Explanation:

Given data:

volume of nitrogen v_1 = 0.08 m^3

P_1 = 150 kPa

T_1 = 200 degree celcius = 473 Kelvin

P_2 = 80 kPa

Polytropic exponent n = 1.4

\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}

putting all value

\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}

\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS

polytropic process is given as

P_1 V_1^n = P_2 V_2^n

150\times 0.08^{1.4} = 80 \times V_2^{1.4}

V_2 = 0.125 m^3

work done = \frac{P_1 V_1 -P_2 V_2}{n-1}

= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}

                  = 5 kJ

4 0
3 years ago
Pelden pushes a box of mass 30 kg with a force of 60 N. What is the
Firlakuza [10]

Answer:

Mass = 30kg

Force = 60N

Acceleration = ?

So

F = m/a

or

a = m/f

a = 30kg/ 60N

0.5ms^2 Answer

7 0
3 years ago
Y’all know what to do… please help
Alisiya [41]

Answer:

A. <u>It</u><u> </u><u>increased</u><u> </u><u>gradually</u><u> </u><u>as</u><u> </u><u>the</u><u> </u><u>reaction</u><u> </u><u>progressed</u><u>.</u>

3 0
3 years ago
Read 2 more answers
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