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3 years ago

6

andy and emily each go to a hardware store to buy wire. The table shows the cost y in dollars for x inches of the wire they need

. andy needs 22 feet of the wire. emily needs 14 yards of the wire. How much will each of them spend for wire?

2 answers:

Andrej [43]3 years ago

6 0

Answer:renegade ?

Step-by-step explanation:

charli left the app

alisha [4.7K]3 years ago

3 0

Andy will spend 15 for her wire and emily would spend 26.75 for her wire

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Given: AABC, AC = 5<br> m C = 90°<br> m A= 22°<br> Find: Perimeter of AABC<br> A<br> C<br> B

Leto [7]

9514 1404 393

Answer:

perimeter ≈ 12.4 units

Step-by-step explanation:

The side adjacent to the angle is given. The relationships useful for the other two sides are ...

Tan = Opposite/Adjacent

Cos = Adjacent/Hypotenuse

From these, we have ...

opposite = 5·tan(22°) ≈ 2.02

hypotenuse = 5/cos(22°) ≈ 5.39

Then the perimeter is ...

P = a + b + c = 2.02 + 5 + 5.39 = 12.41

The perimeter of ∆ABC is about 12.4 units.

7 0

2 years ago

I don’t get this :(

muminat

Ok so for the first one it’s super simple I’m gonna do it as less complicated so it can help you :)

So first we need to convert the mixed number to an improper fraction

1 4/5 = 9/5

Now we need to reduce the numbers greatest common divisor which is 3

3/5 x 6

Now multiply the numbers

Your answer is 18/5 I hoped this help

Now for the second one

this one is a little more complicated and I don’t know how to make it sound easier so I’m gonna tell you the answer which is 580/21

The last one is the same steps we did for the first one which is 27/20

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3 years ago

What is -6(-4d-8.3+3d)

svet-max [94.6K]

Answer:

6d+49.8

If looking for d=8.316 but 6 is repeated

Step-by-step explanation:

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2 years ago

Read 2 more answers

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

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3 years ago

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KatRina [158]

Answer:

Step-by-step explanation:

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2 years ago