Ask question

Ask question

All categories

3 years ago

14

Difference in fraction

"TexFormula1" title=" \frac{1}{2} - 1 \frac{1}{5} " alt=" \frac{1}{2} - 1 \frac{1}{5} " align="absmiddle" class="latex-formula">

1 answer:

jolli1 [7]3 years ago

6 0

The denominator is the bottom number of a fraction.

So in the fraction 3/8 the denominator is 8. In the fraction 5/6 the denominator is 6.

just an example not the answer

the answer is -0.7

You might be interested in

Whats the answer to this

dybincka [34]

Answer:

16 Units.

Step-by-step explanation:

Given:

AC = 2 (x-3)
BD = x + 5

THIS CASE ⇒ AC = BD

⇒ Substitute the values

2 (x - 3) = x + 5

⇒ Clear the value of x

2x - 6 = x + 5

2x - x = 5 + 6

x = 11

⇒ Substitute the value of x in any of the equations

11 + 5 = 16

⇒ Length of each diagonal is 16 units.

5 0

2 years ago

Read 2 more answers

PLSSS HELPPP I WILL GIVE BRAINLIESTTTT!!!!!!!

Anastasy [175]

Answer:

Linear functions are those whose graph is a straight line. A linear function has the following form. y = f(x) = a + bx. A linear function has one independent variable and one dependent variable.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

mihalych1998 [28]

Answer:

10.7cm

Step-by-step explanation:

x^2= 115

x = √115

x = 10.7

5 0

3 years ago

If a number is divisible by 2 and 3, why is it also divisible by 6?

Arada [10]

Answer:

They have 6 when multiplying it

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Find the average velocity of the function over the given interval.

snow_lady [41]

Answer:

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

Average velocity = $\frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx$

= $\frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx$

now integrating

= $\frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )$

= $\frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}$

= $\frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))$

by using formulas

log a-log b = log(a/b)

on simplification , we get

= $\frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)$

= $log(\frac{7}{4} ) -2$

Average velocity of the function over the given interval

= $log(\frac{7}{4} ) -2$

6 0

3 years ago