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3 years ago

Which of the following equations, represents the line with a slope of -2/5 and a y-intercept of 2?

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Y intercept means x=0.

y=mx+c

m is the slope

y=-2/5x+c

Y intercept is 2

y=(-2/5)0+c =2

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Rearrange the equation so r is the independent variable.<br><br> 10q - 5r = 30

Murljashka [212]

Answer:

q = 3 + 1/2r

Step-by-step explanation:

10q - 5r = 30

We want to solve for q

Add 5r to each side

10q - 5r+5r = 30+5r

10q = 30+5r

Divide by 10

10q/10 = 30/10 +5r/10

q = 3 + 1/2r

3 0

4 years ago

Which graph represents a function

Oduvanchick [21]

Answer:

Step-by-step explanation:

Linear as said in it's name is a function that creates (visualy) a straight line.

FROM all the graphs A shows a straight line therefore, the answer.

8 0

3 years ago

Jerod is making candles from beeswax. He has 132.72 ounces of beeswax. If each candle uses 8.4 ounces of beeswax, how many whole

photoshop1234 [79]

Answer:

15 candles

Step-by-step explanation:

132.72÷8.4=15.8

therefore jerod can make 15 whole candles

hope this helps

7 0

3 years ago

HELP!!!! I WILL GIVE BRAINLIEST TO THE FIRST ANSWER!!!!!!!

aleksklad [387]

I would say c. I’m not sure if I’m right if I’m not sorry but good luck

3 0

3 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

6 0

3 years ago