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Stells [14]
3 years ago
13

A macromolecule is added at a concentration of 18 g L−1 to water at a temperature of 10°C. If the resulting osmotic pressure of

this solution is found to be equal to 12 mmHg, estimate the molecular weight of the macromolecule in grams per mole
Chemistry
1 answer:
nlexa [21]3 years ago
4 0

Answer: 26138g/mol

Explanation:

\pi =CRT

\pi = osmotic pressure = 12 mmHg =\frac{1}{760}\times 12=0.016 atm     (760 mmHg= 1atm)

C= concentration in Molarity

R= solution constant  = 0.0821 Latm/Kmol

T= temperature = 10^0C=(10+273)K=283K

For the given solution: 18 g of macromolecule is dissolved to make 1 L of solution.

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution in ml}}

C=\frac{18\times 1000}{M\times 1000ml}=\frac{18}{M}

0.016=\frac{18}{M}\times 0.0821\times 283}

M=26138g/mol

The molecular weight of the macromolecule in grams per mole is 26138.

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