Answer:

Step-by-step explanation:
Vertex form:
where:
is the vertex
is some constant
Given:
- vertex = (-4, -1)
- point on parabola = (-2, -3)
Substitute given values into the formula to find
:





Therefore, the equation of the parabola is:

Isolate the root expression:
![\sqrt[3]{x+1}+2=0\implies\sqrt[3]{x+1}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%2B2%3D0%5Cimplies%5Csqrt%5B3%5D%7Bx%2B1%7D%3D-2)
Take the third power of both sides:
![\sqrt[3]{x+1}=-2\implies(\sqrt[3]{x+1})^3=(-2)^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%7D%3D-2%5Cimplies%28%5Csqrt%5B3%5D%7Bx%2B1%7D%29%5E3%3D%28-2%29%5E3)
Simplify:
![(\sqrt[3]{x+1})^3=(-2)^3\implies x+1=-8](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%2B1%7D%29%5E3%3D%28-2%29%5E3%5Cimplies%20x%2B1%3D-8)
Isolate and solve for

:

Since the cube root function is bijective, we know this won't be an extraneous solution, but it doesn't hurt to verify that this is correct. When

, we have
![\sqrt[3]{-9+1}=\sqrt[3]{-8}=\sqrt[3]{(-2)^3}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-9%2B1%7D%3D%5Csqrt%5B3%5D%7B-8%7D%3D%5Csqrt%5B3%5D%7B%28-2%29%5E3%7D%3D-2)
as required.
Vertex form is
y = a(x - b)^2 + c
here a = -3 and b = -18 so we have
y = a(x + 3)^2 - 18
when x = 0 , y= 0 ( the y-intercept) so:-
0 = a(3^)2 - 18
9a = 18
a = 2
so the parabola is y = 2(x + 3)^2 - 18
x intercepts found as follows:-
2(x + 3)^2 - 18 = 0
(x + 3)^2 = 9
x + 3 = +/- sqrt9 = +/- 3
so x intercepts are 0 and -6 Answer
Answer:
YES
Step-by-step explanation:
There is only one input for one output
Answer:
4010.87
Step-by-step explanation:
3957.60
+ 5.27
+. 48.00
=4010.87