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lara [203]
3 years ago
8

17. Matt sees a video game originally priced at $36. The game is on sale for 25% off. What is the sale price of

Mathematics
2 answers:
Dafna1 [17]3 years ago
6 0

Answer: B

Step-by-step explanation:

36 * .25 = $9

36 - 9 = $27

OR

1 - 0.25 = 0.75

36 * .75 = $27

You're just trying to remove 25% of its cost, so both methods work

Montano1993 [528]3 years ago
4 0

Answer:

It's 27

Step-by-step explanation:

You might be interested in
The diagonal of a square is 60 in, as shown
andre [41]

Answer:

The length of side is 42.4 inches.

Step-by-step explanation:

Given that:

Diagonal of square = 60 inches

As all sides of a square are equal, thus

Side of square = x

The diagonal will be the hypotenuse of a right angled triangle.

Using Pythagorean theorem;

x^2+x^2=(60)^2\\2x^2=3600\\x^2=\frac{3600}{2}\\x^2=1800

Taking square root on both sides

\sqrt{x^2}=\sqrt{1800}\\x=42.4

Hence,

The length of side is 42.4 inches.

5 0
3 years ago
Solve for x in the equation 2x^2+3x-7=x^2+5x+39
Shalnov [3]
Hey there, hope I can help!

\mathrm{Subtract\:}x^2+5x+39\mathrm{\:from\:both\:sides}
2x^2+3x-7-\left(x^2+5x+39\right)=x^2+5x+39-\left(x^2+5x+39\right)

Assuming you know how to simplify this, I will not show the steps but can add them later on upon request
x^2-2x-46=0

Lets use the quadratic formula now
\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}
x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:} a=1,\:b=-2,\:c=-46: x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\left(-46\right)}}{2\cdot \:1}

\frac{-\left(-2\right)+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

Multiply the numbers 2 * 1 = 2
\frac{2+\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2+\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}

\mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \sqrt{\left(-2\right)^2+1\cdot \:4\cdot \:46} \ \textgreater \  \left(-2\right)^2=2^2, 2^2 = 4

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1\cdot \:46=184 \ \textgreater \  \sqrt{4+184} \ \textgreater \  \sqrt{188} \ \textgreater \  2 + \sqrt{188}
\frac{2+\sqrt{188}}{2} \ \textgreater \  Prime\;factorize\;188 \ \textgreater \  2^2\cdot \:47 \ \textgreater \  \sqrt{2^2\cdot \:47}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \  \sqrt{47}\sqrt{2^2}

\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \  \sqrt{2^2}=2 \ \textgreater \  2\sqrt{47} \ \textgreater \  \frac{2+2\sqrt{47}}{2}

Factor\;2+2\sqrt{47} \ \textgreater \  Rewrite\;as\;1\cdot \:2+2\sqrt{47}
\mathrm{Factor\:out\:common\:term\:}2 \ \textgreater \  2\left(1+\sqrt{47}\right) \ \textgreater \  \frac{2\left(1+\sqrt{47}\right)}{2}

\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \  1+\sqrt{47}

Moving on, I will do the second part excluding the extra details that I had shown previously as from the first portion of the quadratic you can easily see what to do for the second part.

\frac{-\left(-2\right)-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1} \ \textgreater \  \mathrm{Apply\:rule}\:-\left(-a\right)=a \ \textgreater \  \frac{2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)}}{2\cdot \:1}

\frac{2-\sqrt{\left(-2\right)^2-\left(-46\right)\cdot \:1\cdot \:4}}{2}

2-\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-46\right)} \ \textgreater \  2-\sqrt{188} \ \textgreater \  \frac{2-\sqrt{188}}{2}

\sqrt{188} = 2\sqrt{47} \ \textgreater \  \frac{2-2\sqrt{47}}{2}

2-2\sqrt{47} \ \textgreater \  2\left(1-\sqrt{47}\right) \ \textgreater \  \frac{2\left(1-\sqrt{47}\right)}{2} \ \textgreater \  1-\sqrt{47}

Therefore our final solutions are
x=1+\sqrt{47},\:x=1-\sqrt{47}

Hope this helps!
8 0
3 years ago
Read 2 more answers
A local restaurant is offering a special deal in which customers can receive one appetizer, one entree, and one dessert for a fi
Dmitriy789 [7]
There are105 different choices.
For 1 appetizer, there are 15 different combinations of entrees and desserts. 1 dessert has 5 entrees you can mix, and since there are 3 desserts, there are 15 choices. It goes the same for every appetizer until there is 7x15. 7Ax15choices equals 105 options.
The customer has 105 meal choices.
5 0
3 years ago
SAT scores: The College Board reports that in 2009, the mean score on the math SAT was 582 and the population standard deviation
Andrews [41]

Answer:

we can conclude that there is no significant evidence to conclude that the mean score in 2010 differs from the mean score in 2009.

Step-by-step explanation:

H0 : μ = 582

H1 : μ < 582

Test statistic :

T = (xbar - μ) ÷ σ/√n

Xbar = 515 ; n = 20 ; σ = 120

T = (515 - 582) ÷ 120/√20

T = -67 / 26.832815

T = 2.50

Pvalue at t score = 2.50 ; df = 19 is 0.0187

At α = 0.0187

Pvalue > α ; Hence, we fail to reject the Null

Hence, we can conclude that there is no significant evidence to conclude that the mean score in 2010 differs from the mean score in 2009.

7 0
3 years ago
Zak has 3/5 pack of pencils. Of these, 2/7 are blue. How many blue pencils does Zak have?
Basile [38]

Answer:

11/35

Step-by-step explanation:

First, you would have to make a common denominator. To do this, multiply these 2 denominator, 5 and 7. You should get 35. Then, you would have to make the numerator equal to the denominator. In this case, multiply 3 to 7 and 2 to 5. Now you have 21/35 and 10/35. Now subtract 21 from 10, and simplify if needed. I hope this helps!

7 0
3 years ago
Read 2 more answers
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