Which of the following statements about the domestication of animals during the agricultural revolution is FALSE?

alisha [4.7K]

Answer:

ye computer ka sawal he .

4 0

2 years ago

A student mixes chemicals A and B together and records the amount of time it takes for a color change to occur. The student repe

k0ka [10]

Answer:

It is mentioned that the student is mixing chemicals A and B and observes the time taken for the color to change. However, in the experiment, it is noticed that the student has repeated the procedure five times and each time he or she is modifying the concentration of chemical B. Thus, it is clear that the concentration of chemical B is the independent variable in the experiment. An independent variable is illustrated as the variable, which is controlled or modified in the experiment.

8 0

3 years ago

A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO

Darya [45]

Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL$

Putting values in above equation, we get:

$2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL$

$M_2=0.336M$

Thus, the concentration of NaOH is, 0.336 M

3 0

3 years ago

What is the name of the ionic compound AlBr3?

Aleksandr [31]

Answer: Correct name will be is aluminum bromide

Explanation:

In a molecular formula , $AlBr_3$

Aluminium atoms present = 1

Bromine atoms present = 3

Charge on aluminium is +3 and charge on bromine is -1.

While naming:

Name of the cation is written first. Simple name of the element is written
After name of cation name of an anions written with suffix 'ide' in the end.

So, the name of $AlBr_3$ will be aluminium bromide.

7 0

3 years ago

Read 2 more answers

A 2.0 molal sugar solution has approximately the same freezing point as 1.0 molal solution of 1) CaCl2 2) CH3COOH 3) NaCl 4) C2H

sertanlavr [38]

Answer:

3) NaCl.

Explanation:

∵ ΔTf = iKf.m

where, i is the van 't Hoff factor.

Kf is the molal depression freezing constant.

m is the molality of the solute.

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

So, for sugar: i = 1.

∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.

For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

So, i for NaCl = 2.

∴ ΔTf for NaCl = iKf.m = (2)(Kf)(1.0 m) = 2 Kf.

So, the right choice is: 3) NaCl.

8 0

3 years ago