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2 years ago

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Which of the following is a unit of mass?

2 answers:

Bogdan [553]2 years ago

7 0

the answer is c: kilogram

explanation: The standard International System of Units (SI) unit of mass is the kilogram (kg). The kilogram is 1000 grams (g), first defined in 1795 as one cubic decimeter of water at the melting point of ice.

larisa86 [58]2 years ago

5 0

Hi there!

Which of the following is a unit of mass?

Well, lets start with pound.

A pound will not be a unit of mass, it is a unit of weight because it holds a force of gravity on an object.

A millimeter is not a unit of mass, because it is a type of measure.

A newton is a unit of force, not a unit of mass.

Therefore, the only unit of mass will be Kilogram.

Hope this helped!~

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Calculate The voltage if the current passing through the wire is 3A, and has a resistance of 10 Q

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2 years ago

Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave r

Iteru [2.4K]

Answer:

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In this problem, we have a microwave photon with wavelength

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3 years ago

Calculate the force needed to give a car of mass 800 kg an acceleration of 2.0 ms−2. plss quick

erik [133]

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<h3>How to calculate force?</h3>

The force needed to push an object can be calculated by multiplying the mass of the object by its acceleration as follows:

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Learn more about force at: brainly.com/question/13191643

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1 year ago

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3 years ago

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A ball is dropped from rest at point O. After falling for some time, it passes by a window of height 3.3 m and it does so in 0.2

stiv31 [10]

Answer:

Speed at which the ball passes the window’s top = 10.89 m/s

Explanation:

Height of window = 3.3 m

Time took to cover window = 0.27 s

Initial velocity, u = 0m/s

We have equation of motion s = ut + 0.5at²

For the top of window (position A)

$s_A=0\times t_A+0.5\times 9.81t_A^2\\\\s_A=4.905t_A^2$

For the bottom of window (position B)

$s_B=0\times t_B+0.5\times 9.81t_B^2\\\\s_A=4.905t_B^2$

$\texttt{Height of window=}s_B-s_A=3.3\\\\4.905t_B^2-4.905t_A^2=3.3\\\\t_B^2-t_A^2=0.673$

We also have

$t_B-t_A=0.27$

Solving

$t_B=0.27+t_A\\\\(0.27+t_A)^2-t_A^2=0.673\\\\t_A^2+0.54t_A+0.0729-t_A^2=0.673\\\\t_A=1.11s\\\\t_B=0.27+1.11=1.38s$

So after 1.11 seconds ball reaches at top of window,

We have equation of motion v = u + at

$v_A=0+9.81\times 1.11=10.89m/s$

Speed at which the ball passes the window’s top = 10.89 m/s

7 0

3 years ago