Answer:
Shawn's kinetic energy is 61.45 J.
Explanation:
Given;
Mass of the system is, 
Displacement of the bike is, 
Time taken is, 
Let the constant velocity be
.
For constant velocity, magnitude of velocity is given as distance by time.
Therefore, 
Now, kinetic energy of a body is given as:

Here, 

Therefore, Shawn's kinetic energy is 61.45 J.
Answer:
The angular displacement is not a length (not measured in meters or feet), so an angular displacement is different than a linear displacement. ... As the object rotates through the angular displacement phi, the point on the edge of the disk moves distance sa along a circular path.
The force on charge Y is the same as the force on charge X
Explanation:
We can answer this problem by applying Newton's third law of motion, which states that:
"When an object A exerts a force on object B (action force), then object B exerts an equal and opposite force on object A (reaction force)"
In this problem, we can identify object A as charge X and object B as charge Y. The magnitude of the electrostatic force between them is given by
(1)
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
According to Newton's third law, therefore, the magnitude of the force exerted by charge X on charge Y is the same as the force exerted by charge Y on charge X (and it is given by eq.(1)), however their directions are opposite.
Learn more about Newton's third law:
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Answer:
fundamental frequency of pipe will be equal to 74 Hz
Explanation:
We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz
Speed of the sound in air is 343 m/sec
We have to find the fundamental frequency for the pipe
Fundamental frequency will be equal to difference of the two adjacent frequency
So fundamental frequency = 370 - 296 = 74 Hz
So fundamental frequency of pipe will be equal to 74 Hz
Answer:
(a) 6650246.305 N/C
(b) 24150268.34 N/C
(c) 6408227.848 N/C
(d) 665024.6305 N/C
Explanation:
Given:
Radius of the ring (r) = 10.0 cm = 0.10 m [1 cm = 0.01 m]
Total charge of the ring (Q) = 75.0 μC =
[1 μC = 10⁻⁶ C]
Electric field on the axis of the ring of radius 'r' at a distance of 'x' from the center of the ring is given as:

Plug in the given values for each point and solve.
(a)
Given:
, 
Electric field is given as:

(b)
Given:
, 
Electric field is given as:

(c)
Given:
, 
Electric field is given as:

(d)
Given:
, 
Electric field is given as: