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Zarrin [17]
3 years ago
13

concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature

(a) what volume (mL) of this solution is needed to make a 1.00L solution of 1.00M phosphoric acid?​
Chemistry
1 answer:
blondinia [14]3 years ago
4 0

Answer:

82.0 mL

Explanation:

Step 1: Given data

  • Concentration of concentrated acid (C₁): 12.2 M
  • Volume of concentrated acid (V₁): ?
  • Concentration of dilute acid (C₂): 1.00 M
  • Volume of dilute acid (V₂): 1.00 L

Step 2: Calculate the required volume of the concentrated acid

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL

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A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade​
egoroff_w [7]

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

Explanation:

Assuming Pressure is constant.

\frac{V_1}{T_1} = \frac{V_2}{T_2}

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

\frac{300}{273} = \frac{V_2}{288}

V_2 = \frac{288*300}{273} \\V_2 = 316.5

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

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How many lone pairs are on the central atom of BrF3?
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A sample of a gas in a rigid container has an initial pressure of 1.049 kPa and an initial temperature of 7.39 K. The temperatur
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Answer:- 4.36 kPa

Solution:- At constant volume, the pressure of the gas is directly proportional to the kelvin temperature.

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Where the subscripts 1 and 2 are representing initial and final quantities.

From given data:

P_1 = 1.049 kPa

P_2 = ?

T_1 = 7.39 K

T_2 = 30.70 K

For final pressure, the equation could also be rearranged as:

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Let's plug in the values in it:

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P_2 = 4.36 kPa

So, the new pressure of the gas is 4.36 kPa.

5 0
4 years ago
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