Given data:
Hydrogen (H) = 3.730 % by mass
Carbon (C) = 44.44%
Nitrogen (N) = 51.83 %
This means that if the sample weighs 100 g then:
Mass of H = 3.730 g
Mass of C = 44.44 g
Mass of N = 51.83 g
Now, calculate the # moles of each element:
# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles
# moles of C = 44.44/12 = 3.703 moles
# moles of N = 51.83/14 = 3.702 moles
Divide by the lowest # moles:
H = 3.730/3.702 = 1
C = 3.703/3.702 = 1
N = 3.702/3.702 = 1
Empirical Formula = HCN
think of like a experamint and take a example of a project
Answer:
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Explanation:
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Answer: The chemical formula of this precipitate is
.
Explanation:
An equation which depicts the chemical reaction of substances in the form of chemical formulas is called a chemical equation.
For example, chemical equation for an aqueous solution of sodium phosphate
and an aqueous solution of magnesium sulfate
are mixed, a precipitate forms is as follows.

Here, trimagnesium phosphate is the precipitate. The chemical formula of this precipitate is
.
Thus, we can conclude that the chemical formula of this precipitate is
.