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3 years ago

From the pictures above, how many processes would have NO EFFECT on the temperature of a room?

Chemistry

1 answer:

zmey [24]3 years ago

8 0

Answer:

b, talking generates no heat and doesn't take away heat

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Please help me I will give a brainleist to anyone who answers

tekilochka [14]

Answer:

Explanation:

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3 years ago

52. A proton is a subatomic particle that has a

kondaur [170]

Answer:

positive charge

Explanation:

Protons are positively charged

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3 years ago

Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ

inessss [21]

Answer:

$\Delta S^{0}$ for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: $\frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)$

$\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]$

where $S^{0}$ represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

$\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K$

So, $\Delta S^{0}$ for the given reaction is -99.4 J/K

7 0

4 years ago

Which statement is true of any chemical reaction

shtirl [24]

Answer:

how can I know

Explanation:

there are no choices

5 0

3 years ago

Which best describes what happens when 50 mL of 0.0010M CaCl2 is added to 50 mL of 0.010M Na2SO4? (The Ksp of CaSO4 = 2.4 × 10–5

Strike441 [17]

For [Ca +2 ]:
0.0010 mol/l · 0.05 l = $5 * 10^{-5} mol$
For [ SO4 -2 ] :
0.01 mol/l · 0.05 l = $5 * 10^{-4}$
Cumulative volume:
50 ml + 50 ml = 10 ml = 0.1 l
[Ca +2 ] = $\frac{5 * 10^{-5} }{0.1} = 5 * 10^{-4}$
[SO4 - 2] = $\frac{5*10^{-4} }{0.1}= 5* 10 ^{-3}$
Qc for CaSO4:
Qc = $5 * 10 ^{-4} * 5 * 10^{-3} = 25 * 10 ^{-7}= 2.5 * 10 ^{-6}$
This is less than Ksp of CaSO4.
Answer: C ) No precipitation will occur.

6 0

3 years ago

Read 2 more answers