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2 years ago

6

The initial concentration of a solution of NaOH is 5.0 M. What volume of the concentrated stock solution is needed to make 200 m

L of .02 M solution? (YOU MUST INCLUDE UNITS IN YOUR ANSWER) *

1 answer:

sveticcg [70]2 years ago

4 0

Answer:

0.8 mL

Explanation:

Use the formula M1V1 = M2V2.

Plug the values in.

5(V1) = 0.02(200)

5V1 = 4

V1 = 0.8 mL

Hope this is right, correct me if I'm wrong!

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