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1 year ago

6

The initial concentration of a solution of NaOH is 5.0 M. What volume of the concentrated stock solution is needed to make 200 m

L of .02 M solution? (YOU MUST INCLUDE UNITS IN YOUR ANSWER) *

1 answer:

sveticcg [70]1 year ago

4 0

Answer:

0.8 mL

Explanation:

Use the formula M1V1 = M2V2.

Plug the values in.

5(V1) = 0.02(200)

5V1 = 4

V1 = 0.8 mL

Hope this is right, correct me if I'm wrong!

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Explanation:

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2 years ago

Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The

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Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of $N_2$ = 8.00 atm

The partial pressure of $O_2$ = 5.00 atm

$K_p$ = 0.0025

The balanced equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initial pressure 8.00 5.00 0

At eqm. (8.00-x) (5.00-x) 2x

The expression of equilibrium constant $K_p$ for the reaction will be:

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Now put all the values in this expression, we get :

$0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}$

By solving the terms, we get:

$x=0.15atm$

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3 years ago

Describe how the size of sediment particles affects their movement during deflation.

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2 years ago

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When liquid bromine is cooled to form a solid, which of the following types of solid would it form?.

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Answer:

If liquid bromine is cooled to form a solid, which type of solid does it form? Brass is made by melting copper and zinc and physically mixing them. As this alloy is cooled, it forms a solid where the copper and zinc are not chemically bonded together.

Explanation:

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1 year ago

Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re

blondinia [14]

M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x <span> 0.0512 => 0.0057856 moles of NaOH

mole ratio:

</span><span>HCl + NaOH = NaCl + H2O
</span><span>
1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- </span><span> 0.0057856 moles NaOH
</span>
(moles HCl ) = <span> 0.0057856 x 1 / 1
</span>
= <span> 0.0057856 moles of HCl
</span>
M ( HCl ) = n / V

M = 0.0057856 / <span>0.0255
</span>
= 0.227 M

Answer A

hope this helps!

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2 years ago

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