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anzhelika [568]
3 years ago
15

If you have 24 g of Mg burn in 32 g Oz, how many g of MgO are produced?

Chemistry
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

Mass = 40 g

Explanation:

Given data:

Mass of Mg = 24 g

Mass of O₂ = 32 g

Moles of MgO = ?

Chemical equation:

2Mg +  O₂ → 2MgO

Number of moles of Mg:

Number of moles of  Mg= Mass /molar mass

Number of moles of Mg= 24g / 24/mol

Number of moles of  Mg= 1 mol

Number of moles of O₂  :

Number of moles of O₂  = Mass /molar mass

Number of moles of O₂  = 32g / 32 g/mol

Number of moles of O₂  = 1 mol

Now we will compare the moles of water with hydrogen and oxygen .

                 Mg            :            MgO

                  2               :               2

                  1                :               1

                 O₂              :                MgO

                  1                :                    2

The number of moles of MgO produced by Mg are less it will be limiting reactant.

Mass of MgO:

Mass = number of moles × molar mass

Mass = 1 mol × 40 g/mol

Mass = 40 g

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timofeeve [1]

Answer:

\boxed {\boxed {\sf 0.80 \ mol\ F}}

Explanation:

We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.

We will convert using dimensional analysis and set up a ratio using Avogadro's Number.

\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.

4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}

Flip the ratio so the units of atoms of fluorine cancel each other out.

4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}

4.8 \times 10^{23}  *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }

Condense into 1 fraction.

\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F

Divide.

0.7970773829 \ mol \ F

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.

0.80 \ mol \ F

4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>

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