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beks73 [17]
3 years ago
10

What metric measurement is similar to a mile?

Chemistry
2 answers:
Dmitriy789 [7]3 years ago
4 0
A kilometer. It's about .62 miles and is the largest unit of measurement for the metric system.
amm18123 years ago
4 0
Kilómetro is just about a mile
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A certain weak acid, ha, has a ka value of 3.6×10−7. part a calculate the percent ionization of ha in a 0.10 m solution. express
slega [8]
Answer is: <span>the percent ionization is 0,19%.
</span>Chemical reaction: HA(aq) ⇄ H⁺(aq) + A⁻(aq).
Ka(HA) = 3,6·10⁻⁷.
c(HA) = 0,1 M.
[H⁺] = [A⁻] = x; equilibrium concentration.
[HA] = 0,1 M - x.
Ka = [H⁺] · [A⁻] / [HA].
0,00000036 = x² / 0,1 M - x.
Solve quadratic equation: x = 0,00019 M.
α = 0,00019 M ÷ 0,1 M · 100% = 0,19%.
8 0
3 years ago
What is a plateau and how can one form?
USPshnik [31]

Answer:

Formation From Under the Earth's Surface

Many plateaus form as magma deep inside the Earth pushes toward the surface but fails to break through the crust. Instead, the magma lifts up the large, flat, impenetrable rock above it

Explanation:

brainliest?

3 0
3 years ago
Read 2 more answers
How does an electron reach an excited state
quester [9]

When an electron quickly occupies an strength state increased than its ground state, it is in an excited state. An electron can end up excited if it is given greater energy, such as if it absorbs a photon, or packet of light, or collides with a close by atom or particle.

5 0
3 years ago
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What are 4 enzymes responsible for digestion along with their substrate and end product​
elena55 [62]

Answer:

4 enzymes responsible for digestion:

1. Salivary amylase ---- substrate: Starch ---- end-product: Maltose  

2. Lipase  ---- substrate: Lipids (fats and oils) ---- end-product: Fatty acids and glycerol

3. Maltase ---- substrate: Maltose ---- end-product: Glucose

4. Protease ---- substrate: Protein ---- end-product: Amino acids

4 0
2 years ago
Given the wavelength of the corresponding emission line, calculate the equivalent radiated energy from n = 4 to n = 2 in both jo
lions [1.4K]

Explanation:

It is given that,

Initial orbit of electrons, n_i=4

Final orbit of electrons, n_f=2

We need to find energy, wavelength and frequency of the wave.

When atom make transition from one orbit to another, the energy of wave is given by :

E=-13.6(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})

Putting all the values we get :

E=-13.6(\dfrac{1}{(4)^2}-\dfrac{1}{(2)^2})\\\\E=2.55\ eV

We know that : 1\ eV=1.6\times 10^{-19}\ J

So,

E=2.55\times 1.6\times 10^{-19}\\\\E=4.08\times 10^{-19}\ J

Energy of wave in terms of frequency is given by :

E=hf

f=\dfrac{E}{h}\\\\f=\dfrac{4.08\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=6.14\times 10^{14}\ Hz

Also, c=f\lambda

\lambda is wavelength

So,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6.14\times 10^{14}}\\\\\lambda=4.88\times 10^{-7}\ m\\\\\lambda=488\ nm

Hence, this is the required solution.

4 0
3 years ago
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