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3 years ago

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A farmer sells 6.1 kilograms of pears and apples at the farmer's market. 4 5 of this weight is pears, and the rest is apples. Ho

w many kilograms of apples did she sell at the farmer's market?

1 answer:

alexandr402 [8]3 years ago

3 0

Answer:

1.6

Step-by-step explanation:

6.1 kilograms - 4.5 kilograms = 1.6 kilograms

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A semicircle has an area of 76.97 squared km. Find it’s radius

shtirl [24]

Answer:

7 km

Step-by-step explanation:

Substitute:

The equation for area of a semi-circle is $\frac{r^{2}\pi }{2}$

A = $\frac{r^{2}\pi }{2}$

76.97 = $\frac{r^{2}\pi }{2}$

Multiply by 2 on both sides:

2(76.97) = ( $\frac{r^{2}\pi }{2}$ )2

153.94 = $r^{2} \pi$

Divide by pi on both sides:

153.94 = $r^{2} \pi$

/pi /pi

49.03 ≈ $r^{2}$

Find the square root:

$\sqrt{49.03} =\sqrt{r^{2} }$

7 = r

7 0

3 years ago

Pleaseeeeeee answer!!!!!!!!!!!!

Reil [10]

-154= -214 - -60

228= 14 - -214

474= 460 -14

5 0

3 years ago

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(will give brainliest!)

Flura [38]

Answer:

D) cot(C) = 1/2.

Step-by-step explanation:

We can go through each choice and examine is validity.

Choice A)

We have:

$\displaystyle \sec B=\frac{3}{7}$

Recall that secant is the ratio of the hypotenuse to the adjacent.

With respect to B, the adjacent is 6 and the hypotenuse is 7.

Therefore, sec(B) should be 7/6 instead.

A is incorrect.

Choice B)

We have:

$\displaystyle \cot B=\frac{3}{2}$

Cotangent is the ratio of the adjacent side to the opposite.

With respect to B, the adjacent side is 6 and the opposite side is 3.

Therefore, cot(B) = 6/3 = 2.

B is incorrect.

Choice C)

C is incorrect for the reasons listed in A.

Choice D)

We have:

$\displaystyle \cot C=\frac{1}{2}$

Again, cotangent is the ratio of the adjacent side to the opposite.

With respect to C, the adjacent side is 3 and the opposite side is 6.

So, cot(C) = 3/6 = 1/2.

Therefore, D is the correct choice!

8 0

3 years ago

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

5 0

3 years ago

Read 2 more answers

U need question problem 2 to solve problem 3

Sergio [31]

Answer:

You are correct

Step-by-step explanation:

Start with 1 1/2. This can be made into an improper fraction which is 3/2

Now multiply both top and bottom of 3/2 by 5

(3*5)/(2 * 5) = 15 / 10

16/10 is just slightly bigger than 15/10

3 0

3 years ago

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