Answer:
Soory
Explanation:
I really dont know but i will send you wait
In our Solar System, Jupiter is the largest planet we have. it has the surface area of 23.71 billion mi^2. it beats all the other planets in both mass and volume.
Explanation:
For an experimental result to be considered acceptable, all relevant variables involved in the experiment must be taken into account, by isolating it, performing it under controlled conditions and modifying the conditions under which it takes place. This, with the objective of excluding alternative explanations in the analisis of the experimental data. Therefore, if these steps are followed appropriately, experimental data are trustworthy. The reliability of the experiment increases when it is replicated by other researchers and the same results are obtained.
Solution :
Speed of the air craft,
= 262 m/s
Fuel burns at the rate of,
= 3.92 kg/s
Rate at which the engine takes in air,
= 85.9 kg/s
Speed of the exhaust gas that are ejected relative to the aircraft,
=921 m/s
Therefore, the upward thrust of the jet engine is given by
![$F=S_{air}(S_{exh}-S_a)+(S_b \times S_{exh})$](https://tex.z-dn.net/?f=%24F%3DS_%7Bair%7D%28S_%7Bexh%7D-S_a%29%2B%28S_b%20%5Ctimes%20S_%7Bexh%7D%29%24)
F = 85.9(921 - 262) + (3.92 x 921)
= 4862635.79 + 3610.32
= ![$4.8 \times 10^6 \ N$](https://tex.z-dn.net/?f=%244.8%20%5Ctimes%2010%5E6%20%5C%20N%24)
Therefore thrust of the jet engine is
.
Answer:
.
Explanation:
The average kinetic energy per molecule of a ideal gas is given by:
![\bar{K}=\frac{3k_{B}T}{2}](https://tex.z-dn.net/?f=%5Cbar%7BK%7D%3D%5Cfrac%7B3k_%7BB%7DT%7D%7B2%7D)
Now, we know that ![\bar{K} = (1/2)m\bar{v}^{2}](https://tex.z-dn.net/?f=%5Cbar%7BK%7D%20%3D%20%281%2F2%29m%5Cbar%7Bv%7D%5E%7B2%7D)
Before the absorption we have:
(1)
After the absorption,
(2)
If we want the ratio of v2/v1, let's divide the equation (2) by the equation (1)
![\frac{v_{2}^{2}}{v_{1}^{2}}=\frac{T_{2}}{T_{1}}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7B2%7D%5E%7B2%7D%7D%7Bv_%7B1%7D%5E%7B2%7D%7D%3D%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D)
![\frac{v_{2}}{v_{1}}=\sqrt{\frac{T_{2}}{T_{1}}}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7B2%7D%7D%7Bv_%7B1%7D%7D%3D%5Csqrt%7B%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D%7D)
![\frac{v_{2}}{v_{1}}=\sqrt{\frac{1340}{335}}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7B2%7D%7D%7Bv_%7B1%7D%7D%3D%5Csqrt%7B%5Cfrac%7B1340%7D%7B335%7D%7D)
![\frac{v_{2}}{v_{1}}=\sqrt{4}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7B2%7D%7D%7Bv_%7B1%7D%7D%3D%5Csqrt%7B4%7D)
Therefore the ratio will be ![\frac{v_{2}}{v_{1}}=2](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7B2%7D%7D%7Bv_%7B1%7D%7D%3D2)
I hope it helps you!