Answer:
180-96 will be the value for c
now do the calculation urself
Answer:
c. 14
Step-by-step explanation:
Let the missing y value be y2.
If the data represent a linear function, then:
![\frac{6 - 2}{2 - 1} = \frac{y_2 - 6}{4 - 2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%20-%202%7D%7B2%20-%201%7D%20%3D%20%5Cfrac%7By_2%20-%206%7D%7B4%20-%202%7D%20)
![\frac{4}{1} = \frac{y_2 - 6}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B1%7D%20%3D%20%5Cfrac%7By_2%20-%206%7D%7B2%7D%20)
![4 = \frac{y_2 - 6}{2}](https://tex.z-dn.net/?f=%204%20%3D%20%5Cfrac%7By_2%20-%206%7D%7B2%7D%20)
Multiply both sides by 2
![4 \times 2 = \frac{y_2 - 6}{2} \times 2](https://tex.z-dn.net/?f=%204%20%5Ctimes%202%20%3D%20%5Cfrac%7By_2%20-%206%7D%7B2%7D%20%5Ctimes%202%20)
![8 = y_2 - 6](https://tex.z-dn.net/?f=%208%20%3D%20y_2%20-%206%20)
Add 6 to both sides
![8 + 6 = y_2 - 6 + 6](https://tex.z-dn.net/?f=%208%20%2B%206%20%3D%20y_2%20-%206%20%2B%206%20)
![14 = y_2](https://tex.z-dn.net/?f=%2014%20%3D%20y_2%20)
The missing value is 14
Answer:
36 Treats
Step-by-step explanation:
The dog trainer started with a bag of 60 treats.
The dog trainer gives treats to 8 dogs with 3 treats meaning 8x3= 24
The trainer gave a total of 24 treats to the 8 dogs.
If the trainer had 60 treats at the start minus 24 (60-24=36).
That means the trainer now has a total of 36 treats left.
A) 1.75p + 12 = 54
1.75p = 42
p = 24 bags
b) 1.75(70) + 12 = b
122.5 + 12 = b
b = $134.50
Answer:
Step-by-step explanation:
Like your other question, let's break it down systematically
6x + 9y - 9(6x - 3y + 8z)
Use the distributive property
6x + 9y - <u>9(6x - 3y + 8z)</u>
6x + 9y - 54x - 27y + 72z
Match like terms
6x - 54x = -48x
9y - 27y = -18y
72z - 48x - 18y