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My name is Ann [436]
2 years ago
7

NEED HELP ASAP ILL GIVE BRAINLIST

Mathematics
1 answer:
FinnZ [79.3K]2 years ago
3 0

Answer:

I think it is C

Step-by-step explanation:

You might be interested in
The sea ice area around the North Pole fluctuates between about 6 million square kilometers in September to 14 million square ki
Aleksandr [31]

Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

Let S(t) represent the amount sea ice around the North Pole in millions of square meters at a given time t,

t is the number of months since January.

Now, we use a cosine curve to model this scenario

Vertical shift will be;

D = ( 6 + 14 ) / 2 = 20 / 2

D = 10

Next is the Amplitude;

|A| = ( 6 - 14 ) / 2

|A| = 4

Now, the horizontal stretch factor will be;

B = 2π / 12

B = π/6

Hence;

S(t) = 4cos( π/6 × t ) + 10 ----------- let this be equation 1

Now we find when there will be less than 9 million square meters of sea ice;

S(t) = 9

so we have

9 = 4cos( π/6 × (t-2) ) + 10

9 - 10 = 4cos( π/6 × (t-2) )

-1 = 4cos( π/6 × (t-2) )

-1/4 = cos( π/6 × (t-2) )

so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2)  -------- let this be equation 2

2π - cos⁻¹( -1/4 ) = π/6 × (t₂-2)  -------- let this be equation 3

so we solve equation 2 and 3

we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )  

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

6 0
2 years ago
A phone company offers two monthly plans. Plan A costs $17 plus an additional $0.09 for each minute of calls. Plan B costs $22 p
Varvara68 [4.7K]

Answer: $53

Step-by-step explanation:

17+ .09m = 9 + .11m

8 = .02m

m = 8/.02= 400 minutes for the two plans to cost the same

9+.11(400) = 9+ 44 = $53 when they cost the same

17+.09(400) = 17 +36  = $53

Please mark brainliest if it helped :)

8 0
2 years ago
Plz help as quick as possible!
kompoz [17]

average =65%

average = (60+70)/(100+100)*100

= 130/200*100

= 65%

6 0
2 years ago
Read 2 more answers
1. Trapezoid BEAR has a height of 8.5 centimeters and parallel bases that measure 6.5 centimeters and 11.5 centimeters. To the n
e-lub [12.9K]
<h3>Given</h3>

1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.

2) Regular pentagon PENTA with side lengths 9 m

<h3>Find</h3>

The area of each figure, rounded to the nearest integer

<h3>Solution</h3>

1) The area of a trapezoid is given by

... A = (1/2)(b1 +b2)h

... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77

The area of BEAR is about 77 cm².

2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...

... A = (1/2)ap

... A = (1/2)(s/(2tan(180°/n)))(ns)

... A = (n/4)s²/tan(180°/n)

We have a polygon with s=9 and n=5, so its area is

... A = (5/4)·9²/tan(36°) ≈ 139.36

The area of PENTA is about 139 m².

6 0
2 years ago
If f(x)=-x^2+3X +5 and g(x)=X^2 +2x, which graph shows the graph of (f+g)(x)?
lana [24]

Answer:

Step-by-step explanation:

+ We find the function (f+g)(x) like

(f+g)(x)= f(x) + g(x) = x^2 +3x+5 + x^2 + 2x = 2x^2 +5x + 5

+ So the graph of (f+g)(x) is a parabole with the sommet (-5/4, 15/8).

Hope that useful for you.

5 0
3 years ago
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