Answer:
1.0 L
Explanation:
Given data
- Initial volume (V₁): 0.35 L
- Initial concentration (C₁): 2.0 M
- Final concentration (C₂): 0.70 M
John and Alex prepared a diluted solution from a concentrated one. We can find the volume of the diluted solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₂ = C₁ × V₁ / C₂
V₂ = 2.0 M × 0.35 L / 0.70 M
V₂ = 1.0 L
It has a high specific heat. Meaning it takes a lot of heat for it to raise up 1 degree
Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
Answer:
sp2
Explanation:
Orbital hybridization is defined as the changes in the orbitals of atoms when they pair with electrons of other atoms to form chemical bonds.
C atoms in C2Cl4 or tetrachloroethene have a total of three bond pairs, two with each chlorine atom and one with other carbon atom and zero lone pairs. Thus, C atoms in C2Cl4 is sp2 hybridized.
Hence, the correct answer is "sp2".