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Salsk061 [2.6K]
3 years ago
12

What mass of Cu(s) is electroplated by running 19.5 A of current through a Cu2 (aq) solution for 4.00 h

Chemistry
1 answer:
oee [108]3 years ago
7 0

Answer:

92.46 g

Explanation:

The reaction is

Cu^{2+}+2e^-\rightarrow Cu

I = Current = 19.5 A

t = 4 hours = 4\times 60\times 60=14400\ \text{s}

F = Faraday constant = 96485.33 C/mol

Molar mass of copper = 63.546 g/mol

Charge is given by

Q=It\\\Rightarrow Q=19.5\times 14400\\\Rightarrow Q=280800\ \text{C}

Moles of electrons is given by

\dfrac{Q}{F}=\dfrac{280800}{96485.33}\\ =2.91\ \text{mol}

Moles of copper is

\dfrac{1}{2}\times \dfrac{Q}{F}=\dfrac{1}{2}\times 2.91\\ =1.455\ \text{mol}

Mass of copper would be

\text{Moles}\times \text{Molar mass of copper}=1.455\times 63.546\\ =92.46\ \text{g}

The mass of copper electroplated is 92.46 g.

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4 years ago
John and Alex were asked to make a 0.70 M solution. John measure out .35 L from the 2.0 M solution before asking how much soluti
nasty-shy [4]

Answer:

1.0 L

Explanation:

Given data

  • Initial volume (V₁): 0.35 L
  • Initial concentration (C₁): 2.0 M
  • Final volume (V₂): ?
  • Final concentration (C₂): 0.70 M

John and Alex prepared a diluted solution from a concentrated one. We can find the volume of the diluted solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₂ = C₁ × V₁ / C₂

V₂ = 2.0 M × 0.35 L / 0.70 M

V₂ = 1.0 L

3 0
3 years ago
Why is water typically used as the heat-absorbing liquid in calorimetry?
jenyasd209 [6]
It has a high specific heat. Meaning it takes a lot of heat for it to raise up 1 degree
8 0
3 years ago
The combustion reaction described in part (b) occurred in a closed room containing 5.56 10g of air
vagabundo [1.1K]

Answer:

Explanation:

Combustion reaction is given below,

C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)

Provided that such a combustion has a normal enthalpy,

ΔH°rxn = -1270 kJ/mol

That would be 1 mol reacting to release of ethanol,

⇒ -1270 kJ of heat

Now,

0.383 Ethanol mol responds to release or unlock,

(c) Determine the final temperature of the air in the room after the combustion.

Given that :

specific heat c = 1.005 J/(g. °C)

m = 5.56 ×10⁴ g

Using the relation:

q = mcΔT

- 486.34 =  5.56 ×10⁴  × 1.005 × ΔT

ΔT= (486.34 × 1000 )/5.56×10⁴  × 1.005

ΔT= 836.88 °C

ΔT= T₂ - T₁

T₂ =  ΔT +  T₁

T₂ = 836.88 °C + 21.7°C

T₂ = 858.58 °C

Therefore, the final temperature of the air in the room after combustion is 858.58 °C

7 0
3 years ago
What is the hybridization of the C atoms in C2Cl4 ?
Dovator [93]

Answer:

sp2

Explanation:

Orbital hybridization is defined as the changes in the orbitals of atoms when they pair with electrons of other atoms to form chemical bonds.

C atoms in C2Cl4 or tetrachloroethene have a total of three bond pairs, two with each chlorine atom and one with other carbon atom and zero lone pairs. Thus, C atoms in C2Cl4 is  sp2 hybridized.

Hence, the correct answer is "sp2".

8 0
3 years ago
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