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sashaice [31]
3 years ago
9

How do you draw acetone using a Bohr model?

Chemistry
1 answer:
Inessa [10]3 years ago
6 0

Explanation:

this is the one i found.....

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Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I
Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

                  H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

At t = 0          0.044M     0.044M              0.177M  

At t=t_{eq}    (0.044-x)M    (0.044-x)M      (0.177+x)M

The expression for K_c for the given reaction follows:

K_c=\frac{[HI]^2}{[H_2]\times [I_2]}

We are given:

K_c=52

Putting values in above equation, we get:

52=\frac{(0.177+x)^2}{(0.044-x)^2}

x=0.0171M

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0
3 years ago
The inca "City of the sun"was ​
SpyIntel [72]
The Inca “City of the Sun” was the city of Cuzco
7 0
3 years ago
The model of a “sea of electrons” helps explain ____.
andriy [413]

Answer:

The correct answer is C.) metallic bonds

Explanation:

Metallic bonds are formed between metal compounds and are very strong. These links are explained by the "sea model of electrons", where valence electrons are ceded by each metal atom, becoming positive ions forming a three-dimensional crystalline network. These electrons move forming a network ("sea") that allows the union of the positive ions formed.

3 0
3 years ago
Read 2 more answers
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
3 years ago
Given the following balanced reaction between nitrogen gas and oxygen gas to produce nitrous oxide gas, how many moles of nitrou
den301095 [7]
Answer is: 3,3 mol of <span>nitrous oxide gas is produced in this chemical reaction.
</span>Chemical reaction: N₂ + O₂ → 2NO.
n(N₂) = 1,65 mol.
n(NO) = ?
from reaction n(N₂) : n(NO) = 1 : 2.
1,65 mol : n(NO) = 1 : 2.
n(NO) = 3,3 mol.
n - amount of substance.
4 0
3 years ago
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