Answer: Last week, Nate and I counted all the inventory.
Explanation: all other choices are passive voices
this sentence follows a clear subject + verb + object construct that's why it is an active voice. In fact, sentences constructed in the active voice add impact to your writing. but on the other hand With passive voice, the subject is acted upon by the verb.
Ape x
Answer:
So the fraction of proeutectoid cementite is 44.3%
Explanation:
Given that
cast iron with 0.35 % wtC and we have to find out fraction of proeutectoid cementite phase when cooled from 1500 C to room temperature.
We know that
Fraction of proeutectoid cementite phase gievn as
Now by putting the values
So the fraction of proeutectoid cementite is 44.3%
Answer:
- hoop stress
- longitudinal stress
- material used
all this could led to the failure of the garden hose and the tear along the length
Explanation:
For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :
hoop stress ( which acts along the circumference of the pipe):
αh = EQUATION 1
and Longitudinal stress ( acting along the length of the pipe )
αl = EQUATION 2
where p = water pressure inside the hose
d = diameter of hose, T = thickness of hose
we can as well attribute the failure of the hose to the material used in making the hose .
assume for a thin cylindrical pipe material used to be
≥ 20
insert this value into equation 1
αh = = 60/2 = 30 psi
the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose
If the pump stops working, malfunctions, or becomes clogged, it will not supply enough fuel to the injectors.
Answer:
maximum roll-off factor is 0.7
Explanation:
given data
rate of output data = 1,000,000 bits/sec
cutoff frequency fc = 850 kHz
solution
we know bandwidth frequency is same as that of bandwidth
we apply here fc formula that is
fc = ω ( 1 + α ) ..........1
here
ω = data rate ÷ 2 .............2
ω = 1000 ÷ 2
ω = 500000 Hz
so put now value in eq 1
fc = ω ( 1 + α )
850000= 500000 ( 1 + α )
solve it we get
α = 0.7
so, maximum roll-off factor is 0.7