The driveshaft of an automobile is being designed to transmit 238 hp at 3710 rpm. Determine the minimum diameter d required for
a solid steel shaft if the allowable shear stress in the shaft is not to exceed 7200 psi.
1 answer:
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Answer:
Elastic modulus of steel = 202.27 GPa
Explanation:
given data
long = 110 mm = 0.11 m
cross section 22 mm = 0.022 m
load = 89,000 N
elongation = 0.10 mm = 1 × m
solution
we know that Elastic modulus is express as
Elastic modulus = ................1
here stress is
Stress = .................2
Area = (0.022)²
and
Strain = .............3
so here put value in equation 1 we get
Elastic modulus =
Elastic modulus of steel = 202.27 × Pa
Elastic modulus of steel = 202.27 GPa