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SCORPION-xisa [38]
4 years ago
8

The driveshaft of an automobile is being designed to transmit 238 hp at 3710 rpm. Determine the minimum diameter d required for

a solid steel shaft if the allowable shear stress in the shaft is not to exceed 7200 psi.

Engineering
1 answer:
AURORKA [14]4 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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A DC generator turns at 2000 rpm and has an output of 200 V. The armature constant is 0.5 V-min/Wb, and the field constant of th
WITCHER [35]

Answer:

b. 10A

Explanation:

Using the formula, E= k × r×I

200= 0.5 ×2000×0.02×I

200=20×I

Dividing with 20

I = 200/20= 10A

4 0
3 years ago
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The best way to identify common masonry problems is to call the engineer.<br> True or False
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Answer:

True

Explanation:

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3 years ago
A family member who hasn’t worked with computers before has decided to change jobs. You’ve been asked to explain some of the bas
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3 years ago
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Radioactive wastes are temporarily stored in a spherical container, the center of which is buried a distance of 10 m below the e
a_sh-v [17]

Answer:

Outside temperature =88.03°C

Explanation:

Conductivity of air-soil from standard table

   K=0.60 W/m-k

To find temperature we need to balance energy

Heat generation=Heat dissipation

Now find the value

We know that for sphere

q=\dfrac{2\pi DK}{1-\dfrac{D}{4H}}(T_1-T_2)

Given that q=500 W

so

500=\dfrac{2\pi 2\times .6}{1-\dfrac{2}{4\times 10}}(T_1-25)

By solving that equation we get

T_2=88.03°C

So outside temperature =88.03°C

6 0
3 years ago
A monatomic ideal gas undergoes a quasi-static process that is described by the function p(????)=p1+3(????−????1) , where the st
Alenkasestr [34]

A pure gas made up only of atoms. The noble gases argon, krypton, and xenon are some examples.

Concepts:

Perfect gas law: Work performed on the system: PV = nRT W = -∫PdV

Energy preservation formula: U = Q + W

Reasoning:

W = nRT ln(Vi/Vf) when the process is isothermal.

The temperature is said to be constant, and we are given n, Pfinal, and Vfinal.

Calculation information:

(A) A process that is isothermal has a constant temperature.

PV = nRT, and hence, constant

nRT = PV = 101000 Pa*25*10-3 m3

For a process that is isothermal, W = nRT ln(Vi/Vf).

W/(nRT)=3000 J/(101000 Pa*25*10-3 m3)=-1.19

(The gas produces -W of labor.)

Vi = (25*10-3 m3)/3.28 = 7.62*10-3 m3 = 7.62 L where Vf/Vi = exp(1.19) = 3.28 Vi (b) for a perfect gas PV = nRT. 101000 Pa*25*10-3 m3 = (8.31 J/K) T. T = 303.85 K.

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5 0
1 year ago
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