Answer:
The concentration is simply 36%
Step-by-step explanation:
In this question, we are concerned with calculating the concentration of a new mixture formed from mixing some liters of each of two vinegar variants of different concentrations.
We proceed as follows;
The concentration of the new solution will contain 12% of 13L vinegar A and 70% of 9L vinegar B
13L of vinegar A will contain 13 * 12% = 13 * 0.12 = 1.56
9L of 70% vinegar B will contain 9 * 70% = 9 * 0.7 = 6.3
Now, the new mixture has a total volume of 13 + 9 = 22L
The concentration of the new mixture will thus be;
(1.56 + 6.3)/22
= 0.357 and that’s approximately 0.36 or simply 36%
1n=n Answer:
Step-by-step explanation:
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P(A) =0.54
P(B)= 0.68
P'(A)= 1-0.54 = 0.46
P'(B)= 1- 0.68 = 0.32
The probability of neither of both event will occur:
= P'(A)×P'(B)
=0.46 × 0.32
=0.1472
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NB: values with 10 is to the first power.