In the compound cah2 calcium has an oxidation number of 2+ and hydrogen has an oxidation number of

Chemistry

1 answer:

sesenic [268]3 years ago

7 0

The oxidation number of H is -1.

Sum of the oxidation numbers in each element = charge of the complex

CaH₂ has 1 Ca atom and 2H atoms. The charge of the complex is zero. Let’s say Oxidation number of H is "a".

Then,

(+2) + 2 x a = 0

+2 + 2a = 0

2a = -2

a = -1

Hence, the oxidation number of Hydrogen atom in CaH₂ is -1

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Aluminum reacts with excess hydrochloric acid to form aqueous aluminum chloride and 190.6 ml of hydrogen gas (collected over wat

melamori03 [73]

Answer:

0.1296 grams of aluminum reacted

Explanation:

Equation of reaction:

2Al + 6HCl = 2AlCl3 + 3H2

From the ideal gas equation

PV = nRT

n = PV/RT

P = (25.2/760)atm + 0.89atm = 0.923 atm

V = 190.6 ml = 190.6cm^3

R = 82.057cm^3.atm/gmol.K

T = 26°C = 26+273K = 299K

n = 0.923×190.6/82.057×299 = 0.0072 moles of H2

From the equation of reaction

3 moles of hydrogen gas is formed from 2 moles of aluminum

Therefore, 0.0072 moles of hydrogen gas is formed from (0.0072×2/3 = 0.0048) moles of aluminum

Number of moles of aluminum that reacted = 0.0048 moles

Mass of aluminum that reacted = number of moles × MW = 0.0048 × 27 = 0.1296 grams

8 0

4 years ago

Read 2 more answers

Draw the alkyne formed when 2,3-dichloropentane is treated with an excess of strong base such as sodium amide.

Xelga [282]

Hi! Thank you for posting your question here at Brainly. I hope I would be able to help you with my answer.

When an alkyne such as 2,3-dichloropentane is treated with excess sodium amide, a two-step elimination reaction will happen. The reaction would then yield the final product in the form of 2-pentyne. Its structure is shown in the attached image.