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Gnesinka [82]
2 years ago
5

15. conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests t

hat ___ are likely intermediates during these reactions
Chemistry
1 answer:
son4ous [18]2 years ago
7 0

Conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that electrophilic reagents are likely intermediates during these reactions.

Two double bonds and one single bond divide a conjugated diene into two halves. Nonconjugated (Isolated) Dienes have more than one single bond separating two double bonds. Two double bonds are joined to the same atom to form cumulated dienes.

Reagents that function by acquiring electrons or sharing electrons that once belonged to a foreign molecule are referred to as electrophilic reagents, or electrophiles, in some cases. Electrophiles are molecules with a positive charge and a lack of electrons that can react by exchanging electron pairs with nucleophiles, which have many electrons. Epoxides, hydroxy amines, nitroso and azoxy derivatives, nitrenium ions, and elemental sulfur are significant electrophiles.

To know more about Electrophiles refer to: brainly.com/question/21773561

#SPJ4

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A mixture of CO2 and Kr weighs 31.7 g and exerts a pressure of 0.665 atm in its container. Since Kr is expensive, you wish to re
elena-s [515]

Answer:

11.94 grams of carbon dioxide were originally present.

19.94 grams of krypton can you recover.

Explanation:

Mass of carbon dioxide gas = x

Mass of krypton gas = y

x + y = 31.7 g

Moles of carbon dioxide gas = n_1=\frac{x}{44 g/mol}=

Moles of krypton gas = n_2=\frac{y}{84 g/mol}=

Mole fraction of krpton =\chi '

Total pressure of the mixture = P = 0.665 atm

Partial pressure of carbon dioxide gas = p

Partial pressure of krypton gas before removal  of carbon dioxide gas = p'

Partial pressure of krypton gas after removal  of carbon dioxide gas = p'' = 0.309 atm

p' = p'' = 0.309 atm

0.665 atm = p + 0.309 atm

p = 0.665 atm - 0.306 atm = 0.359 atm

Partial pressure of krypton can also be given by :

p'=P\times \chi '

0.309 atm=0.665 atm\times \frac{n_2}{n_1+n_2}

0.309 atm=0.665 atm\times \frac{\frac{y}{84}}{\frac{x}{44}+\frac{y}{84}}

0.4645=\frac{\frac{y}{84}}{\frac{x}{44}+\frac{y}{84}}..[2]

Solving [1] and [2]:

x = 11.94 g

y = 19.76 g

11.94 grams of carbon dioxide were originally present.

19.94 grams of krypton can you recover.

7 0
4 years ago
How many molecules are in 3.0 moles of O2
Alex777 [14]
Answer:  " <span>1.8 * 10²⁴ molecules of O₂ " .
________________________________________</span>

3.0 moles O₂ * (6.02 * 10²³ molecules O₂ / 1 mol O₂) = 


[ (3.0) *(6.02 * 10²³) ] molecules O₂
                                  = 1.806 * 10²⁴ ; round to 2 significant figures.
                                              = 1.8 * 10²⁴ molecules of O₂ .
______________________________________________________
5 0
3 years ago
The concentration of H30 in your swimming pool is 4 x 10^-5 M. What is the pH of your pool? O a.-4.4 Ob.4.4 Oc. 0.00004 O d.-0.6
mariarad [96]

Answer:

b. 4.4

Explanation:

pH is related to the concentration of H₃O⁺ through the following equation:

pH = -log([H₃O⁺]) = -log(4 x 10⁻⁵)

pH = 4.4

8 0
4 years ago
What is the correct equation for water gas​
garik1379 [7]

Answer:

Water-gas A mixture of carbon monoxide (CO) and hydrogen (H2) produced by passing steam over red-hot coke using the endothermic reaction C + H2O # CO + H2.

Explanation:

7 0
3 years ago
Determine what the spin state of each complex will be using the spectrochemical series along with your chemical intuition. Pleas
seropon [69]

Answer:

A) high spin complex

B) low spin complex

Explanation:

A) VCI3(H20)3 is a high spin complex and this is because the complex has a weak field ligands all . this weak field ligands makes it impossible for pairing to take place

B) Fe(NH3)23 is a low spin complex and this is because the complex is made up of strong field ligands, this strong field ligands makes it possible for paring to take place

note : Ligands in which its donor atoms are ; Nitrogen,phosphorous or carbon are considered strong ligands

3 0
4 years ago
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