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Gnesinka [82]
2 years ago
5

15. conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests t

hat ___ are likely intermediates during these reactions
Chemistry
1 answer:
son4ous [18]2 years ago
7 0

Conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that electrophilic reagents are likely intermediates during these reactions.

Two double bonds and one single bond divide a conjugated diene into two halves. Nonconjugated (Isolated) Dienes have more than one single bond separating two double bonds. Two double bonds are joined to the same atom to form cumulated dienes.

Reagents that function by acquiring electrons or sharing electrons that once belonged to a foreign molecule are referred to as electrophilic reagents, or electrophiles, in some cases. Electrophiles are molecules with a positive charge and a lack of electrons that can react by exchanging electron pairs with nucleophiles, which have many electrons. Epoxides, hydroxy amines, nitroso and azoxy derivatives, nitrenium ions, and elemental sulfur are significant electrophiles.

To know more about Electrophiles refer to: brainly.com/question/21773561

#SPJ4

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A student uses a dye to change the colour of his tee-shirt. he fills a metal bucket with water. When the bucket is heated, what
Tanya [424]

Answer:

The particles begin to vibrate faster and more.

Explanation:

Adding heat to matter increases the energy, thus creating more movement. Eventually, the bucket will melt, turning to a liquid. While it is a sold, it still has particle movement, just not enough to break volume or shape.

8 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
Find the fugacity coefficient of a gaseous species of mole fraction 0.4 and fugacity 25 psia in a mixture at a total pressure of
Oksana_A [137]

<u>Answer:</u> The fugacity coefficient of a gaseous species is 1.25

<u>Explanation:</u>

Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as \bar{\phi}

Mathematically,

\bar{\phi}_i=\frac{\bar{f_i}}{p_i}

Partial pressure of the gas is expressed as:

p_i=\chi_iP

Putting this expression is above equation, we get:

\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}

where,

\bar{\phi}_i = fugacity coefficient of the gas

\bar{f_i} = fugacity of the gas = 25 psia

\chi_i = mole fraction of the gas = 0.4

P = total pressure = 50 psia

Putting values in above equation, we get:

\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25

Hence, the fugacity coefficient of a gaseous species is 1.25

8 0
3 years ago
ALGEBRA 1 SEM 1
olganol [36]

Answer:

This is the best answer your mom

Explanation:

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In this experiment when both crests combine they produce a __________ spot.
zvonat [6]

Answer:

meteor

Explanation:

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3 years ago
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