Question

Consider this reaction: H2S + HNO3 S + NO + H2O Reduction half-reaction: N+5 + 3e- N+2 Oxidation half-reaction: S-2 S + 2e- After balancing the chemical equation, what are the coefficients for these compounds?

Answer 1

After balancing the chemical equation, what are the coefficients for these compounds?

H2S      

⇒ 3

HNO3    

⇒ 2

Works for EDG

Answer 2

Answer:

Coefficient of $H_2S$ = 3

Coefficient of $HNO_3$ = 2

Coefficient of $NO$ = 2

Coefficient of $H_2O$ = 4

Coefficient of $S$ = 3

Explanation:

Overall reaction

$H_2S + HNO_3\rightarrow S + NO + H_2O$

Reduction half-reaction:

$N^{+5} + 3e^-\rightarrow N^{+2}$...(1)

Oxidation half-reaction:

$S^[-2}\rightarrow S + 2e^-$...(2)

2×(1) + 3×(2)

$2N^{+5} + 6e^-+3S^[-2}\rightarrow 2N^{+2}+3S + 6e^-$

$2N^{+5} +3S^[-2}\rightarrow 2N^{+2}+3S$

$3H_2S + 2HNO_3\rightarrow 3S + 2NO + 4H_2O$

Coefficient of $H_2S$ = 3

Coefficient of $HNO_3$ = 2

Coefficient of $NO$ = 2

Coefficient of $H_2O$ = 4

Coefficient of $S$ = 3