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tresset_1 [31]
3 years ago
8

Consider this reaction: H2S + HNO3 S + NO + H2O Reduction half-reaction: N+5 + 3e- N+2 Oxidation half-reaction: S-2 S + 2e- Afte

r balancing the chemical equation, what are the coefficients for these compounds?
Chemistry
2 answers:
Yuri [45]3 years ago
8 0

After balancing the chemical equation, what are the coefficients for these compounds?

H2S      


⇒ 3

HNO3    


⇒ 2

Works for EDG



dezoksy [38]3 years ago
6 0

Answer:

Coefficient of H_2S = 3

Coefficient of HNO_3 = 2

Coefficient of NO = 2

Coefficient of H_2O = 4

Coefficient of S = 3

Explanation:

Overall reaction

H_2S + HNO_3\rightarrow S + NO + H_2O

Reduction half-reaction:

N^{+5} + 3e^-\rightarrow N^{+2}...(1)

Oxidation half-reaction:

S^[-2}\rightarrow S + 2e^-...(2)

2×(1) + 3×(2)

2N^{+5} + 6e^-+3S^[-2}\rightarrow 2N^{+2}+3S + 6e^-

2N^{+5} +3S^[-2}\rightarrow 2N^{+2}+3S

3H_2S + 2HNO_3\rightarrow 3S + 2NO + 4H_2O

Coefficient of H_2S = 3

Coefficient of HNO_3 = 2

Coefficient of NO = 2

Coefficient of H_2O = 4

Coefficient of S = 3

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