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Law Incorporation [45]
3 years ago
6

Please answer this question

Chemistry
1 answer:
ZanzabumX [31]3 years ago
6 0

Answer:

Is the fixed number of water molecules present in one formula unit of a substance

Explanation:

When copper sulphate is heated in a china dish, the blue colomed crystal changes to a white powder due to the removal of molecules of water of crystallization

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Explain why the following chemical equation represents a Lewis acid-base reaction. H+ + NH3 —>NH4+
lozanna [386]

Answer:

Due to an electron-pair acceptor and donor.

Explanations:

<em><u>Lewis acid</u></em> can be defined as an electron-pair acceptor. An example is Hydrogen ion(H+). This is because it is a proton and it distributes positive charge which means that it accepts electrons(negative charge).

<em><u>Lewis base</u></em> can be defined as an electron-pair donor. This is because it donates electrons to be accepted by the proton. An example is ammonia(NH3).

7 0
3 years ago
6th grade science i will give brainliest
Alexandra [31]
0.2 m/s! keep in mind, speed= distance divided by time :D
7 0
3 years ago
5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H
cricket20 [7]
We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572.  That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0
3 years ago
Suppose that a certain atom possesses only four distinct energy levels. Assuming that all transitions between levels are possibl
olya-2409 [2.1K]

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6

4 0
3 years ago
Chemistry unit 3 lesson 14<br> unit test connexus
Leno4ka [110]

Answer: what is the question

7 0
2 years ago
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