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3 years ago

What is a speed of a car if it covers 130 km in 2 hours?

Physics

2 answers:

Flauer [41]3 years ago

8 0

Answer:

65km/h

Explanation:

s=d/t

s=130km/2h

= 65km/h

inysia [295]3 years ago

3 0

Answer:

65 km per hour

Explanation:

130/2=65

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A graph of acceleration against force

enot [183]

The equation of the graph is

Force = (mass) x (acceleration) .

The graph is a straight line that passes through the origin,
and its slope is the mass of the object being studied.

5 0

3 years ago

A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9

Andreyy89

Answer:

$d = 0.0306 m$

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

$U + K = constant$

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

$\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0$

$7.05 + 30.5 = \frac{0.266}{r}$

$r = 7.08 \times 10^{-3} m$

so distance moved by the particle is given as

$d = r_1 - r_2$

$d = 0.0377 - 0.00708$

$d = 0.0306 m$

6 0

3 years ago

Temperature is a measure of _ of the particles in an object

djverab [1.8K]

energy is the correct answer to fill the blank bb :)

3 0

3 years ago

As compared to the asthenosphere, the lithosphere is ____________. a. hotter and more able to flow b. hotter and less able to fl

Mnenie [13.5K]

Answer:

its a solid but can flow

Explanation:

those answers to choose from are wrong

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2 years ago

An object is lifted from the surface of aspherical planet to an altitude equal to the radius of the planet.As a result, what hap

serg [7]

An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet.

As a result, the object's <em>mass remains the same</em>, and its <em>weight decreases</em> to 1/4 of whatever it is when the object is on the planet's surface.

8 0

3 years ago