A nuclear can hold 2 electrons
Answer:
1.78 rad/s
1.70344 rad/s
Explanation:
v = Velocity = 0.8 m/s
m = Mass of person = 60 kg
= Distance between center of mass of person and pole = 0.45 m
= New distance between center of mass of person and pole = 0.46 m
I = Moment of inertia
Angular speed is given by
![\omega_1=\dfrac{v}{r_1}\\\Rightarrow \omega_1=\dfrac{0.8}{0.45}\\\Rightarrow \omega_1=1.78\ rad/s](https://tex.z-dn.net/?f=%5Comega_1%3D%5Cdfrac%7Bv%7D%7Br_1%7D%5C%5C%5CRightarrow%20%5Comega_1%3D%5Cdfrac%7B0.8%7D%7B0.45%7D%5C%5C%5CRightarrow%20%5Comega_1%3D1.78%5C%20rad%2Fs)
The angular speed is 1.78 rad/s
In this system the angular momentum is conserved
![L_1=L_2\\\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow mr_1^2\omega_1=mr_2^2\omega_2\\\Rightarrow \omega_2=\dfrac{r_1^2\omega_1}{r_2^2}\\\Rightarrow \omega_2=\dfrac{0.45^2\times 1.78}{0.46^2}\\\Rightarrow \omega_2=1.70344\ rad/s](https://tex.z-dn.net/?f=L_1%3DL_2%5C%5C%5CRightarrow%20I_1%5Comega_1%3DI_2%5Comega_2%5C%5C%5CRightarrow%20mr_1%5E2%5Comega_1%3Dmr_2%5E2%5Comega_2%5C%5C%5CRightarrow%20%5Comega_2%3D%5Cdfrac%7Br_1%5E2%5Comega_1%7D%7Br_2%5E2%7D%5C%5C%5CRightarrow%20%5Comega_2%3D%5Cdfrac%7B0.45%5E2%5Ctimes%201.78%7D%7B0.46%5E2%7D%5C%5C%5CRightarrow%20%5Comega_2%3D1.70344%5C%20rad%2Fs)
The new angular speed is 1.70344 rad/s
Answer:
ive never done this befor but i think its 36 times aroud earth a day
Explanation:
384400/400=961
961% of 27 days is 40minuets
1440/40=36