Answer:
by catching it
Explanation:
if you catch it it will not break
Answer:
HB=131.69
Explanation:
Given that
Diameter , D= 10 mm
Depth of indentation ,d= 1.55 mm
Load ,P =500 kg
Brinell hardness is given as
Now by putting the values in the above equation we get
HB=131.69
Therefore the hardness of the material will be 131.69 HB.
Answer:
A) 282.34 - j 12.08 Ω
B) 0.0266 + j 0.621 / unit
C)
A = 0.812 < 1.09° per unit
B = 164.6 < 85.42°Ω
C = 2.061 * 10^-3 < 90.32° s
D = 0.812 < 1.09° per unit
Explanation:
Given data :
Z ( impedance ) = 0.03 i + j 0.35 Ω/km
positive sequence shunt admittance ( Y ) = j4.4*10^-6 S/km
A) calculate Zc
Zc = =
= = 282.6 < -2.45°
hence Zc = 282.34 - j 12.08 Ω
B) Calculate gl
gl =
d = 500
z = 0.03 i + j 0.35
y = j4.4*10^-6 S/km
gl =
=
= 0.622 < 87.55 °
gl = 0.0266 + j 0.621 / unit
C) exact ABCD parameters for this line
A = cos h (gl) . per unit = 0.812 < 1.09° per unit ( as calculated )
B = Zc sin h (gl) Ω = 164.6 < 85.42°Ω ( as calculated )
C = 1/Zc sin h (gl) s = 2.061 * 10^-3 < 90.32° s ( as calculated )
D = cos h (gl) . per unit = 0.812 < 1.09° per unit ( as calculated )
where : cos h (gl) =
sin h (gl) =
Answer:
cultivation - preparing and planting crops
domestication - capturing, taming, and breeding animals
hunting and gathering - obtaining food from the wild
Explanation:
moo
Answer:
Explanation:
Given that:
f = 250 Hz
= 2%
= 600 Hz
= 0.5 to 1.5 increment by 0.05
For 250 Hz = 250 cycle/sec
M = 0.98 , 1.02
At 0.7183 value of damping ratio the error value was 2% at 0.98 value of M
At 0.6330 value of damping ratio the error value was 2% at 1.02 value of M.
Hence, the damping ratio of the transducer must be placed between 0.6330 to 0.7183