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Readme [11.4K]
3 years ago
10

Calculate the density of the FCC nickel lattice with an interstitial hydrogen in the centered position of the unit cell. You may

assume that there is no lattice dilation due to the presence of the hydrogen atom. a=3.524A, At.Wt. = 58.7g/mole,
Engineering
1 answer:
Anastaziya [24]3 years ago
4 0

Answer:

\rho=8907.94\ Kg/m^3

Explanation:

Given that

a=3.524 A

At.Wt. ,M= 58.7 g/mole,

 For FCC

 Z = 4

4r=\sqrt2\ a

The density given as

\rho=\dfrac{ZM}{N_Aa^3}

\rho=\dfrac{4\times 58.7\times 10^{-3} }{ 6.023\times 10^{23}\times (3.524\times 10^{-10})^3}

\rho=8907.94\ Kg/m^3

So the density is \rho=8907.94\ Kg/m^3

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Answer:

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solving for y100 =(2+2y) y) \times (1/0.015) [\frac{(3+2y) y}{(3+2\sqrt{5} y)}]^{2/3} \times 0.004^{1/2}

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