Question

Calculate the density of the FCC nickel lattice with an interstitial hydrogen in the centered position of the unit cell. You may assume that there is no lattice dilation due to the presence of the hydrogen atom. a=3.524A, At.Wt. = 58.7g/mole,

Answer 1

Answer:

$\rho=8907.94\ Kg/m^3$

Explanation:

Given that

a=3.524 A

At.Wt. ,M= 58.7 g/mole,

 For FCC

 Z = 4

$4r=\sqrt2\ a$

The density given as

$\rho=\dfrac{ZM}{N_Aa^3}$

$\rho=\dfrac{4\times 58.7\times 10^{-3} }{ 6.023\times 10^{23}\times (3.524\times 10^{-10})^3}$

$\rho=8907.94\ Kg/m^3$

So the density is $\rho=8907.94\ Kg/m^3$