Answer:
Answer is
The distance moved is : 42m
The magnitude and direction of the displacement: 10m
Explanation:
The distance moved is:
22+16+4=42
The magnitude and direction of the displacement:
22-16+4=10
Answer:
The three blanks for this answer, are
1. volumen
2. moles
3. Temperature and pressure.
So, Avogadro's law states that the volume of a gas is directly proportional to the moles of the gas when temperature and pressure stay the same
Explanation:
Imagine you have 10 moles of a gas which is contained in 50 L. How many moles of that gas, you will have if the volumen has been reduced to 10 L. (Of course, don't forget that T° and pressure are the same)
There is an equation like this, initial moles /initial volume = moles at the end/volume at the end, (Avogadro law for gases), so 10/50 =moles at the end/10. When u operate, moles at the end = (10 x 10) / 50.
Moles at the end are 2. Did u get it?. Volumen has been reduced, also the moles.
Answer: 3.72 M
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = 
t = age of sample = 15.0 minutes
a = let initial amount of the reactant = 10.0 M
a - x = amount left after decay process = ?
The concentration of 
in a solution after 15.0 minutes have passed is 3.72 M
Answer:
False
Explanation:
Half life is the time period at which the concentration of the radioactive substance in decay reduced to half.
<u>Thus, if the hydrogen-3 has gone 2 half lives, it means that it has first reduced to its half and then again the half of what it was, i.e. 1/4</u>
Thus, after two successive half-lives, the concentration must be 1/4 of the initial concentration and hence, the statement is false.
Answer:
C) Q < K, reaction will make more products
Explanation:
- 1/8 S8(s) + 3 F2(g) ↔ SF6(g)
∴ Kc = 0.425 = [ SF6 ] / [ F2 ]³
∴ Q = [ SF6 ] / [ F2 ]³
∴ [ SF6 ] = 2 mol/L
∴ [ F2 ] = 2 mol/L
⇒ Q = ( 2 ) / ( 2³)
⇒ Q = 0.25
⇒ Q < K, reaction will make more products
