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xenn [34]
3 years ago
8

Find the image of the point (-5,-2) under ​

Mathematics
1 answer:
____ [38]3 years ago
4 0
Find the image of the point (−2,−7) under ,so it’s (12,-1)
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Negative -5/8 - 1/2= <br> I wanna know fast anyone??
alexira [117]

Answer" -9/8

by-step explanation:

-5/8 - 1/2 = -9/8

Simplify: -9/8= 1  1/8

3 0
3 years ago
After one hour in flight, an airplane is located 100 miles north and 200 miles west of the airport. What is the velocity of the
MAVERICK [17]
I think 224 miles an hour
3 0
3 years ago
11
yulyashka [42]
The answer is C because it like adding 11.40+00.40 and that would be 12:20
3 0
3 years ago
If people who bought 4 souvenir spent $2 for each one,how much did all the people who bought 4 souvenir spend in all ?
puteri [66]

I believe it is $0.50.

$2 divided by 4 equals $0.50.

8 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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