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deff fn [24]
3 years ago
13

Need Answer: FIND THE SLOPE OF THE LINE THAT PASSES THROUGH THE POINT (6,-4) and(3,2)?

Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

first you take the y-axis of the the second point which is 2 and subtract it from the first y-axis which is -4. You then do the same with the x-axis and then divide your y-axis from the x-axis.

it should look like this- 2-(-4) over

3-6 subtract then divide to get -2

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Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?
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Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

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Step-by-step explanation:

Given the equation

5x - y = 12

converting the line into the slope-intercept form y = mx+b, where m is the slope

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Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

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where m is the slope of the line and (x₁, y₁) is the point

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y-y_1=m\left(x-x_1\right)

y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)

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Add 3 to both sides

y-3+3=-\frac{1}{5}\left(x+2\right)+3

y=-\frac{1}{5}x+\frac{13}{5}

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

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