Answer:
Step-by-step explanation:
This is a simple proportion problems.
7 kilogram weight attache to a spring stretches = 6 meters
1 kilogram would stretch = 6/7 m
Therefore 42 kilograms would stretch = (6/7 x 42)meters
= 36 meters.
Sorry, cannot just give you answers without your input.
I'd suggest that you look up online or in your textbook each of the items under "Type of Boundary." The results you'd get will likely help you fill in the rest of the boxes.
Answer:
ΔRHS ≅ ΔNKW
Step-by-step explanation:
We are given that, in the triangles RHS and NKW.
∠H = ∠K
Side HS = KW.
∠S = ∠W
Now, using the ASA congruence criteria, which states that when two corresponding angles of the triangles are equal with the included side between them is equal, then both the triangles are congruent.
Hence, according to ASA criteria, ΔRHS ≅ ΔNKW.
Given :
Three points , P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .
To Find :
The length of sides .
Given :
We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :
Length of PQ :
Length of QR :
:
Length of RP :
Hence , this is the required solution .
Answer:
y = -3/4x + 3
Step-by-step explanation:
y - 9 = -3/4 (x-8)
y-9 = -3/4x -6
y = -3/4x - 6 + 9
y = -3/4x + 3
hope this helps if not sorry
