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Sonbull [250]
3 years ago
6

What is her velocity? 1.5 m/s 2 m/s 2.5 m/s 5 m/s

Physics
2 answers:
fiasKO [112]3 years ago
7 0

Answer:

There is no actual question attached to this, to get a real answer be sure to include the documents/question that is provided on your work.  

Explanation:

Xelga [282]3 years ago
6 0

Answer:

C. 2.5

Explanation:

This is the answer to that one question on Edge nuity, I got it right.

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How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n
hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N  

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m  

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)  

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q =  r*sq rt F[4pieo]

 q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

 891 excess electrons must be present on each sphere  

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