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Vilka [71]
3 years ago
10

A particle (q = 4.0 mC, m = 50 g) has a velocity of 25 m/s in the positive x direction when it first enters a region where the e

lectric field is uniform (60 N/C in the positive y direction). What is the speed of the particle 5.0 s after it enters this region?
Physics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

The speed of the particle is 34.66 m/s.

Explanation:

Given that,

Mass of particle = 50 g

Charge of particle = 4.0 mC

Velocity = 25 m/s

Electric field = 60 N/C

Time = 5.0 sec

We need to calculate the speed in y direction

Using formula of speed

v=a\times t

Where, a = acceleration

v=\dfrac{F}{m}\times t

v=\dfrac{qEt}{m}

Put the value in to the formula

v=\dfrac{4.0\times10^{-3}\times60\times5.0}{50\times10^{-3}}

v=24\ m/s

We need to calculate the speed of the particle

v=\sqrt{v_{x}^2+v_{y}^2}

Put the value into the formula

v=\sqrt{25^2+24^2}

v=34.66\ m/s

Hence, The speed of the particle is 34.66 m/s.

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