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vekshin1
3 years ago
5

A magnet attracts more iron dusts at its end​

Physics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

Its a MAGNETIC FIELD that can let a magnet attracts more iron dusts

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Which statement describes nuclear fission
Harlamova29_29 [7]

The Splitting of a nucleus

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3 years ago
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What separates the terrestrial planets from the jovian or gas planets in space?
Flura [38]
In our solar system, terrestrial planets are separated from the gas giants by the asteroid belt. The asteroid belt is a region in the solar system between Mars and Jupiter where asteroids are located. Gas giants do not have a solid surface and possible a small rocky core. The gas giants are Jupiter, Saturn, Uranus and Neptune. The first four planets, Mercury, Venus, Earth and Mars.  
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3 years ago
A skater with an initial speed of 7.30 m/s stops propelling himself and begins to coast across the ice, eventually coming to res
Rufina [12.5K]

Answer:

a. a= 1.029 ms⁻²

b. S=25.89 m

Explanation:

given

initial speed is u = 7.30 m/sec

final speed is v = 0 m/sec

mu_k = 0.105

kinetic frictional force is Fk = mu_k×m×g

mu_k×m×g = m×a

m cancels

mu_k×g = a

deccelaration a = mu_k×g = 0.105×9.8 =1.029 ms⁻²

b) using v²-u² = 2aS

0²-7.3² = -2×1.029×S

53.29=2.058×S

S = 53.29/2.058

S=25.89 m

6 0
3 years ago
What is an incident angle
Hunter-Best [27]

Answer:In geometric optics, the angle of incidence is the angle between a ray incident on a surface and the line perpendicular to the surface at the point of incidence, called the normal. The ray can be formed by any wave: optical, acoustic, microwave, X-ray and so on. In the figure below, the line representing a ray makes an angle θ with the normal. The angle of incidence at which light is first totally internally reflected is known as the critical angle. The angle of reflection and angle of refraction are other angles related to beams.

Explanation:tik tok: Uh.amy07

5 0
3 years ago
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Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak
Mashutka [201]

Answer:

Part a)

\Delta \phi = 2.2 \pi

Part b)

f = 411.3 Hz

Explanation:

As we know that the observer is standing in front of one speaker

So here the path difference of the two sound waves reaching to the observer is given as

\Delta x = 3\sqrt2 - 3

\Delta x = 1.24 m

now phase difference is related with path difference as

\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)

\Delta \phi = \frac{2\pi}{\lambda}(1.24)

here in order to find the wavelength

\lambda = \frac{c}{f}

\lambda = \frac{340}{300} = 1.13

now we have

\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi

Part b)

Now we know that when phase difference is odd multiple of \pi

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

\Delta \phi = 3\pi

so we have

3\pi = \frac{2\pi}{\lambda}(1.24)

so we have

\lambda = 0.827

now we have

\frac{340}{f} = 0.827

f = 411.3 Hz

4 0
3 years ago
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