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tekilochka [14]
3 years ago
14

How is matter conserved through cellular respiration

Chemistry
1 answer:
Basile [38]3 years ago
5 0

Answer:

In cellular respiration, complex molecules containing carbon react with oxygen to produce carbon dioxide and other materials. ... Matter is conserved during cellular respiration because atoms are conserved in physical and chemical processes

Explanation:

I hope this helps

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Determine the genotypes of offspring 1-8.
8_murik_8 [283]
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4 0
3 years ago
The halpy of vaporization of H2O at 1 atm and 100 C is 2259 kJ/kg. The heat capacity of liquid water is 4.19 kJ/kg.C, and the he
Naddik [55]

Answer: Option (a) is the correct answer.

Explanation:

The given data is as follows.

        C_{p}_{liquid} = 4.19 kJ/kg ^{o}C

        C_{p}_{vaporization} = 1.9 kJ/kg ^{o}C

Heat of vaporization (\DeltaH^{o}_{vap}) at 1 atm and 100^{o}C is 2259 kJ/kg

        H^{o}_{liquid} = 0

Therefore, calculate the enthalpy of water vapor at 1 atm and 100^{o}C as follows.

            H^{o}_{vap} = H^{o}_{liquid} + \DeltaH^{o}_{vap}        

                                   = 0 + 2259 kJ/kg

                                   = 2259 kJ/kg

As the desired temperature is given 179.9^{o}C and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and 179.9^{o}C is calculated as follows.

             H^{D}_{liq} = H^{o}_{liquid} + C_{p}_{liquid}(T_{D} - T_{o})

                             = 0 + 4.19 kJ/kg ^{o}C \times (179.9^{o}C - 100^{o}C)

                              = 334.781 kJ/kg

Hence, enthalpy of water vapor at 10 bar and 179.9^{o}C is calculated as follows.

               H^{D}_{vap} = H^{o}_{vap} + C_{p}_{vap} \times (T_{D} - T_{o})

             H^{D}_{vap} = 2259 kJ/kg + 1.9 \times (179.9 - 100)            

                              = 2410.81 kJ/kg

Therefore, calculate the latent heat of vaporization at 10 bar and 179.9^{o}C as follows.

       \Delta H^{D}_{vap} = H^{D}_{vap} - H^{D}_{liq}              

                         = 2410.81 kJ/kg - 334.781 kJ/kg

                         = 2076.029 kJ/kg

or,                      = 2076 kJ/kg

Thus, we can conclude that at 10 bar and 179.9^{o}C latent heat of vaporization is 2076 kJ/kg.

3 0
4 years ago
Uranium in the isotope below had 140 nutrons​
Brut [27]

Answer:

It has 140 neutrons because Mass number= No of protons + no of neutrons

4 0
4 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 59.56 g of nacl in 165.1 g of h2o. express your answer to
nikitadnepr [17]
The general formula for mass percent of a solution is:

% m/m = [grams of solute] / [grams of solution] * 100

And grams of solution = grams of solute + grams of solvent.

So, in our problem:

Solute = NaCl => mass of solute = 59.56 g

Solvent = H2O => mass of solvent = 165.1 g

=> mass of solution = 59.56 g + 165.1 g = 224.66 g

=> % m/m = [59.56 / 224.66] * 100 = 26.51 g (using four significant figures).

Answer: 26.51%
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Answer:

BUBBLE SUPER BUBBLE

Explanation:

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