Answer:
Please find the complete question in the attached file.
Explanation:
It would only be radioactive if the DNA molecule that employed the poly-T rand as templates. Its other molecule of the daughter would not have been radioactive as it did not need dATP for its replication. While each strand of the second molecule includes t, simultaneous reproduction dATP from both daughter molecules is needed so that each of those is radioactive.
First we will calculate free energy change:
ΔG₀ = ΔH₀ - (T * ΔS₀)
= - 793 kJ - (298 * - 0.319 kJ/K) = - 698 kJ
We know the relation between free energy change and cell potential is:
ΔG₀ = - n F E⁰ where
F = Faraday's constant = 96485 C/mol
n = 2 (given by equation that the electrons involved is 2)
ΔG₀ = - 2 x 96485 x E⁰
- 698 kJ = - 2 x 96485 x E⁰
E⁰ = (698 x 1000) / (2 x 96485) = 3.62 volts
B.
And maybe put your question in the English/Literature tag next time lol
Your answer to your question is: 1s² 2s² 2p⁶
Answer:
0.825 M
Explanation:
The osmotic pressure is a colligative property, that can be calculated using the following expression.
π = M × R × T
where,
π is the osmotic pressure
M is the molarity
R is the ideal gas constant
T is the absolute temperature (24°C + 273 = 297 K)
M = π / R × T = 20.1 atm / (0.08206 atm.L/mol.K) × 297 K = 0.825 M
