If 31.8 grams of LiCl are dissolved in 225 grams of water, what is the concentration of the solution in percent by mass?
2 answers:
Answer: 12.4 %
Explanation:
To calculate the mass percent of solution, we use the formula:
Given :
mass of solute (LiCl) = 31.8 grams
mass of solvent (water) = 225 grams
Mass of solution = mass of solute + mass of solvent = 31.8 g + 225 g= 256.8 g
Thus concentration of the solution in percent by mass is 12.4%
You might be interested in
<h2>Answer:</h2>
<h2>Explanations</h2>
The complete balanced equation for the given reaction is expressed as;
Given the following parameters
Mass of CH4 = 5.90×10^−3 g = 0.0059grams
Determine the moles of methane
According to stoichimetry, 1 mole of methane produces 2 moles of water, hence the moles of water required will be:
Determine the mass of water produced
Therefore the mass of water produced from the complete combustion of 5.90×10−3 g of methane is 1.33 * 10^-2grams