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Mashcka [7]
4 years ago
5

If 31.8 grams of LiCl are dissolved in 225 grams of water, what is the concentration of the solution in percent by mass? 

Chemistry
2 answers:
erastovalidia [21]4 years ago
8 0
(31.8/(225+31.8))(100)=12.38317757% LiCl
melomori [17]4 years ago
3 0

Answer: 12.4 %

Explanation:

To calculate the mass percent of solution, we use the formula:

\text{Mass percent of solution}=\frac{\text{Mass of solute}}{\text{mass of solution}}\times 100

Given :

mass of solute (LiCl) = 31.8 grams

mass of solvent (water) = 225 grams

Mass of solution = mass of solute + mass of solvent = 31.8 g + 225 g= 256.8 g

\text{Mass percent of solution}=\frac{31.8}{256.8g}\times 100=12.4%

Thus concentration of the solution in percent by mass is 12.4%

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