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sveticcg [70]
3 years ago
9

En una escuela se recibieron plumas de diferentes patrocinadores. Por parte de la sociedad de padres compraron 4 1⁄4 cajas. La S

ociedad de Alumnos aporto 2 5/6 cajas. Y 3 3⁄4 cajas regalo Un Programa de Educación ¿Cuántas cajas de plumas son en total?
Mathematics
1 answer:
Ludmilka [50]3 years ago
8 0

Answer:

10\frac {5}{6} boxes

Step-by-step explanation:

Given that pens received from the parents' society = 4 \frac 1 4 boxes.

Pens received from the Student Society = 2 \frac 56 boxes.

Pens received as gift boxes = 3 \frac 3 4 boxes.

So, the total number of boxes of pens received = 4 \frac 1 4 + 2 \frac 56 + 3 \frac 3 4 boxes

=\frac {17}{4} + \frac {17}{6} +\frac{15}{4}\\\\=\frac {65}{6}\\\\=10\frac {5}{6}.

Hence, the total number of boxes of pens received = 10\frac {5}{6} boxes.

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Today there are a total of six toll-free area codes: 800, 844, 855, 866, 877, and 888. Assume that all seven digits for the rest
Ludmilka [50]

Answer:

6 \times 10^{7}

Step-by-step explanation:

Total number of toll-free area codes = 6

A complete number will be of the form:

800-abc-defg

Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.

Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.

Considering: 800-abc-defg

The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.

Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:

Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = 10^{7}

Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = 6 \times 10^{7}

4 0
4 years ago
I need help with this i can’t graph
zaharov [31]

Answer:

(-2,-5), (0,-4), (3,5) (1,1)

Solution:

Only (0,-4) is on the line

(-2,-5), (1,1), and (3,5) is in the orange

(5,5)  Isn't right because it's not on the line nor in the orange

4 0
3 years ago
The height of a triangle is 8ft greater than the base. The area of the triangle is 136.5 square ft. Find the length of the base
mixer [17]

Answer:

the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

Step-by-step explanation:

Note that the formula for the area of a triangle is A = (1/2)(base)(height).  Let's abbreviate that to A = (1/2)(b)(h).   We are told that h = b + 8.

Then A = 136.5 = (1/2)(b)(b + 8), or

               (after multiplying both sides by 2)

          A = 273 = b^2 + 8b

                which, when put into standard quadratic form, becomes:

b^2 + 8b - 273 = 0

The coefficients of this quadratic are a = 1, b = 8 and c = -273.

Thus, the discriminant is b^2 - 4ac, or 64 - 4(1)(-273) = 1156 = 17^2.

The roots are then

      -8 ± √1156            -8 ± 17

x = --------------------  =  ------------ = 9/2 and -25/2

              2                          2

Only the root 9/2 makes sense here, because measurements of length are positive.

Thus, the base is 9/2 ft and the height is 9/2 + 8, or 25/8, ft.

3 0
4 years ago
Find the following products:
baherus [9]

Answer:

i. x^2 – 1

ii. x^3 – 1

iii. x^4 - 1

Step-by-step explanation:

Products are obtained by multipliyng each left term by each rigth term as follows:

i. (x- 1)(x+ 1) = (x^2  – x + x - 1) = x^2 – 1 (equal terms with opposite sign substracts and the result is 0)

ii. (x- 1)(x^2 + x + 1) = (x^3 – x^2 + x^2 – x + x – 1) = x^3 – 1

iii. (x- 1)(x³ + x² + x + 1) = (x^4 – x^3 + x^3 – x^2 + x^2 – x + x – 1) = x^4 - 1

7 0
3 years ago
-1/3-(-3/5)= <br> reduce to the simplest form.
Ne4ueva [31]

Answer:

1/15

Step-by-step explanation:

-1/3 -(-3/5)

-1/3 + 3/5

(-1 × 5) / (3 × 5) + (3 × 3) / (5 × 3)

-5 / 15 + 6 / 15 = 1/15

6 0
3 years ago
Read 2 more answers
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