Question

tm. A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10 L to 15 L. The final pressure is __________ atm. 1.5 7.5 0.67 3.3 15

Answer 1

Answer:

The final pressure will be 0.67 atm.

Explanation:

Using Boyle's law  

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,  

V₁ = 10 L

V₂ = 15 L

P₁ = 1.0 atm

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${1.0}\times {10}={P_2}\times {15} atm$

${P_2}=\frac{{1.0}\times {10}}{15} atm$

${P_2}=0.67\ atm$

The final pressure will be 0.67 atm.