Answer:
1. False
2. True
3. True
Explanation:
1- False —> The relation between electric potential and electric field is given such that
Therefore, for a uniform E field, electric potential is linearly proportional to the distance.
2- True —> The electric field lines always cross the equipotential lines perpendicularly.
3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:
There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.
reaction, opposite directions, and more
Answer:
P = 251, 3 W
Explanation:
The intensity is defined as the power emitted per unit area
I = P / A
Since sound is distributed in all directions spherical shape, the area of a sphere is
A = 4π r²
let's clear the power and replace
P = I A
P = I (4π r²)
let's calculate
P = 5.00 (4π 2²)
P = 251, 3 W
Answer:
W = 506.75 N
Explanation:
tension = 2300 N
Rider is towed at a constant speed means there no net force acting on the rider.
hence taking all the horizontal force and vertical force in consideration.
net horizontal force:
F cos 30° - T cos 19° = 0
F cos 30° = 2300 × cos 19°
F = 2511.12 N
net vertical force:
F sin 30° - T sin 19°- W = 0
W = F sin 30° - T sin 19°
W = 2511.12 sin 30° - 2300 sin 19°
W = 506.75 N
Answer:
F = 1480.77N
Explanation:
In order to calculate the required force to push the container with a constant velocity, you take into account the the sum of force on the container is equal to zero. Furthermore, you have for an incline the following sum of forces:
(1)
F: required force = ?
W: weight of the container = 1800N
N: normal force = weigth
α: angle of the incline = 28°
g: gravitational acceleration = 9.8m/s^2
μ: coefficient of friction = 0.4
You solve the equation (1) for F and replace the values of the other parameters:
The required force to push the container for the incline with a constant velocity is 1480.77N
