<span>(4) 19.6 N</span>
On Earth's surface, a mass of 1kg <span>exerts a force(weight) of 9.81 N
So the weight= 9.81x2.00
=19.62N
=19.6N</span>
Answer:


Explanation:
Given:
- mass of the object,

- elastic constant of the connected spring,

- coefficient of static friction between the object and the surface,

(a)
Let x be the maximum distance of stretch without moving the mass.
<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>


where:
N = m.g = the normal reaction force acting on the body under steady state.


(b)
Now, according to the question:
- Amplitude of oscillation,

- coefficient of kinetic friction between the object and the surface,

Let d be the total distance the object travels before stopping.
<em>Now, the energy stored in the spring due to vibration of amplitude:</em>

<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>




<em>is the total distance does it travel before stopping.</em>