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jeyben [28]
3 years ago
10

Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial accel

eration (in m/s2) of this massif it is released and allowed to move?
Physics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

acceleration = 0.8181 m/s²

Explanation:

given data

mass = 1.1 kg

apart d = 1 m

charge q = 10 μC

to find out

What is the initial acceleration

solution

we know that acceleration is

acceleration = \frac{force}{mass}   .................1

here force = k \frac{q1q2}{r^2}

here q1 q2 is charge and r is distance and Coulomb constant k = 9 × 10^{9} Nm²/C²

force = 9*10^{9} \frac{(10*10^{-6})^2}{1^2}

force = 0.9 N

so  from equation 1

acceleration = \frac{0.9}{1.1}

acceleration = 0.8181 m/s²

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Answer:

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Explanation:

Given:

Angle of projection of the rocket is, \theta=33.6

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A vector at an angle \theta with the horizontal can be resolved into mutually perpendicular components; one along the horizontal direction and the other along the vertical direction.

If a vector 'A' makes angle \theta with the horizontal, then the horizontal and vertical components are given as:

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Here, as the velocity is a vector quantity and makes an angle of 33.6 with the horizontal, its Y component is given as:

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Plug in the given values and solve for u_y. This gives,

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