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jeyben [28]
2 years ago
10

Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial accel

eration (in m/s2) of this massif it is released and allowed to move?
Physics
1 answer:
sweet-ann [11.9K]2 years ago
6 0

Answer:

acceleration = 0.8181 m/s²

Explanation:

given data

mass = 1.1 kg

apart d = 1 m

charge q = 10 μC

to find out

What is the initial acceleration

solution

we know that acceleration is

acceleration = \frac{force}{mass}   .................1

here force = k \frac{q1q2}{r^2}

here q1 q2 is charge and r is distance and Coulomb constant k = 9 × 10^{9} Nm²/C²

force = 9*10^{9} \frac{(10*10^{-6})^2}{1^2}

force = 0.9 N

so  from equation 1

acceleration = \frac{0.9}{1.1}

acceleration = 0.8181 m/s²

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6 0
3 years ago
What two factors affect the rate of acceleration of an object?
Masja [62]

For help with this answer, we look to Newton's second law of motion:

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Since the question seems to focus on acceleration, let's get
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Here's the equation again:

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Now the answer jumps out at us:  The rate of acceleration of an object
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zysi [14]
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