Answer:

Explanation:
wavelength 
d = 0.190 mm = 0.190 × 10⁻³ m
D = 1.91 m
By using the formula:


The first maximum will appear at an angle
from the beam axis
Answer:
Explanation:
Given
angle through which ball is launched
Range of ball=50 m
Range of projectile is 

u=22.136 m/s
If ball is thrown straight upward



s=25 m
(b)For Projectile time of flight is


t=3.19 s
Answer:
small car since they weigh less than a bus
Explanation:
Answer:

Explanation:
Hello,
In this case, considering that the acceleration is computed as follows:

Whereas the final velocity is 28.82 m/s, the initial one is 0 m/s and the time is 4.2 s. Thus, the acceleration turns out:

Regards.
Answer:
D. 2^(3/2)
Explanation:
Given that
T² = A³
Let the mean distance between the sun and planet Y be x
Therefore,
T(Y)² = x³
T(Y) = x^(3/2)
Let the mean distance between the sun and planet X be x/2
Therefore,
T(Y)² = (x/2)³
T(Y) = (x/2)^(3/2)
The factor of increase from planet X to planet Y is:
T(Y) / T(X) = x^(3/2) / (x/2)^(3/2)
T(Y) / T(X) = (2)^(3/2)